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3 years ago

9

The histogram shows the number of payphones that were active by year in a large city. How many payphones would you expect to be

active between 1976 and 1980? over 200 between 150 and 200 between 50 and 100 fewer than 50

1 answer:

tangare [24]3 years ago

6 0

Answer:

Between 150 and 200

Step-by-step explanation:

i just did the assignment .

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Lonna uses 8.2 pints of blue paint and white paint to paint her bedroom walls. 2 5 of this amount is blue paint, and the rest is

vova2212 [387]

Answer:

the number of pints of blue paint did she use for painting her bedroom walls is 1.875 pints

Step-by-step explanation:

The computation of the number of pints of blue paint did she use for painting her bedroom walls is shown below:

= Total pint × blue paint

= 7.5 × (1 - 3 ÷ 4)

= 7.5 × 1 ÷ 4

= 1.875 pints

Hence, the number of pints of blue paint did she use for painting her bedroom walls is 1.875 pints

5 0

3 years ago

The pink paper for the book Giver

Leni [432]

I think its the promise to not share it with anyone idk

4 0

3 years ago

Please Help me! 20 points

malfutka [58]

Answer:

-9/4 ÷ (-2/3)

Step-by-step explanation:

-(2 1/4) ➡ -9/4

-2/3 ➡ (again a reciprocal needed) -3/2 since we need the result to be positive both expression should remain negative so the answer is -9/4 ÷ -2/3

6 0

3 years ago

(x-yi)(3+5i) is the conjugate of 6+24i

Nataly_w [17]

Answer:

x=-3

y=3

(-3-3i)(3+5i)

Step-by-step explanation:

$(x-yi)(3+5i)\\=3x+5xi-3yi+5y\\=(3x+5y)+(5x-3y)i\\$

and we have that must equal

6-24i

3x+5y=6

5x-3y=-24 and if we work it we found out that the solutions are

x=-3 and

y=3

5 0

3 years ago

After the mill in a small town closed down in 1970, the population of that town started decreasing according to the law of expon

wlad13 [49]

Answer:

$P_o = \frac{143000}{e^{-20*0.01303024661}}=110193.69$

And we can round this to the nearest up integer and we got 110194.

Step-by-step explanation:

The natural growth and decay model is given by:

$\frac{dP}{dt}=kP$ (1)

Where P represent the population and t the time in years since 1970.

If we integrate both sides from equation (1) we got:

$\int \frac{dP}{P} =\int kdt$

$ln|P| =kt +c$

And if we apply exponentials on both sides we got:

$P= e^{kt} e^k$

And we can assume $e^k = P_o$

And we have this model:

$P(t) = P_o e^{kt}$

And for this case we want to find $P_o$

By 1990 we have t=20 years since 1970 and we have this equation:

$143000 = P_o e^{20k}$

And we can solve for $P_o$ like this:

$P_o = \frac{143000}{e^{20k}}$ (1)

By 2019 we have 49 years since 1970 the equation is given by:

$98000 = P_o e^{49k}$ (2)

And replacing $P_o$ from equation (1) we got:

$98000=\frac{143000}{e^{20k}} e^{49k} =143000 e^{29k}$

We can divide both sides by 143000 we got:

$\frac{98000}{143000} =0.685 = e^{29k}$

And if we apply ln on both sides we got:

$ln(0.685) = 29k$

And then k =-0.01303024661[/tex]

And replacing into equation (1) we got:

$P_o = \frac{143000}{e^{-20*0.01303024661}}=110193.69$

And we can round this to the nearest up integer and we got 110194.

7 0

3 years ago