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PSYCHO15rus [73]
3 years ago
6

In need of some help please.

Mathematics
1 answer:
Hatshy [7]3 years ago
8 0
By the Pythagorean theorem
  50^2 = x^2 +(x +34)^2
  2500 = 2x^2 +68x + 1156
  x^2 +34x -672 = 0
  (x -14)(x +48) = 0
  x = 14 or -48

The distance from the wall to the base of the ladder is 14 ft.

_____
7-24-25 is a Pythagorean triple. The dimensions here are double those values. It can be handy to know a few of the Pythagorean triples, as that can let you write down the answers to problems without having to go through the equations.
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Danielle weighs 3 1/5 pounds less than Teresa if Diane weighs 54 2/3 pounds how many how much does Theresa weigh
andrew11 [14]
16/5=48/15
54 2/3= 164/3
164-48=144
she weighs 144
4 0
4 years ago
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You have 6 reindeer, Jebediah, Bloopin, Balthazar, Ezekiel, Prancer, and Lancer and you want to have 4 fly your
Sav [38]

Answer:

360

Step-by-step explanation:

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4 years ago
Suppose the supply and demand for a certain textbook are given by ​supply: p equals one half q squared comma ​demand: p equals n
vampirchik [111]

Answer:

Demand quantity: 6.3246

Supply quantity: 4.4721

Step-by-step explanation:

Supply equation:

p = (1/2) * q^2

Demand equation:

p = -(1/2) * q^2 + 30

(p is the price, q is the quantity)

If the price p is equal to 10, then we can calculate:

Supply quantity:

10 = 0.5 * q^2

q^2 = 20

q = 4.4721

Demand quantity:

10 = -0.5 * q^2 + 30

0.5 * q^2 = 20

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8 0
3 years ago
Here are some points, have a good day!
Mnenie [13.5K]

Answer:

.....

Step-by-step explanation:

................thanks.......

6 0
3 years ago
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What is the common factor for the following monomials 12x to the third power 18x to the second power 6 x to the fourth power
hichkok12 [17]

12x^3=\boxed{2}\cdot2\cdot\boxed{3}\cdot \boxed{x}\cdot \boxed{x}\cdot x\\\\18x^2=\boxed{2}\cdot\boxed{3}\cdot3\cdot \boxed{x}\cdot \boxed{x}\\\\6x^4=\boxed{2}\cdot\boxed{3}\cdot \boxed{x}\cdot \boxed{x}\cdot x\cdot x\\\\LCF(12x^3,\ 18x^2,\ 6x^4)=\boxed{2}\cdot\boxed{3}\cdot\boxed{x}\cdot\boxed{x}=6x^2\\\\Answer:\ \boxed{\boxed{6x^2}}

6 0
3 years ago
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