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3 years ago

Can someone answer plzzzz

Mathematics

1 answer:

telo118 [61]3 years ago

8 0

Answer:

6,882,000 miles

Step-by-step explanation:

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Using the greatest common factor for the terms, how can you write 56 + 32 as a product?

WARRIOR [948]

The answer is c ...use the distrubutive property to check it

8 0

3 years ago

Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

3 years ago

Ok sorry about all the questions

ss7ja [257]

Answer:

D is the answers for the question

Step-by-step explanation:

please mark me as brainlest

4 0

3 years ago

Read 2 more answers

Please solve -(6x+7)+8=19

JulijaS [17]

-6x-7+8=19 and then add your like terms so it’s -6x+1=19 and then subtract one on both sides so it’s -6x=18 so x=-3

3 0

3 years ago

Please answer. 30 points.

kotegsom [21]

Answer:

Srry umm can you zoom in I cant see srry!

Step-by-step explanation:

7 0

3 years ago