All categories

4 years ago

Item 6 Solve the system of linear equations by substitution. x=2y+7 3x−2y=3

Mathematics

1 answer:

grin007 [14]4 years ago

8 0

X=2 Y=-4.5 I got this by substituting the value of x into the equation 3(2y+7)-2y=3 and solving.

You might be interested in

For Vectors, how do you know which axis you go off of when drawing a vector's direction. I see some going off x-axis but some go

aksik [14]

Answer:

If you read the description it says you are going southeast as a pilot. The reason is because you are going Southeast, you can't go Southeast anywhere without the angle where it is for B

5 0

3 years ago

Read 2 more answers

The coefficients corresponding to k = 0, 1, 2, ..., 6 in the expansion of (x + y)6

Ber [7]

I think the answer is c.

3 0

3 years ago

Professor Ivy has following scores on her final exams: 97 88 66 55 89 72 94 32 84 89 72 76 77 Express answers rounded correctly

Gre4nikov [31]

Answer:

The rest of the question:

Find Mean, Median, Mode, 25th Percentile, 75th Percentile, Maximum, Minimum, Range and IQR.

Let's begin by placing the data points in order from least to greatest:

32 55 66 72 72 76 77 84 88 89 89 94 97

n = 13

1) Mean sometimes called the average = the sum of the data over its number

Mean =( 32+55+66+72+72+76+77+84+88+89+89+94+97 )/13 =

= 991/13 = 76.23 ≈ 76.2 (to the nearest tenth)

2) Median is the middle data point = 77

3) Mode is any number within a set that occurs the most often

Mode = 72 and 89

We will making a data in suitable form to find the remaining requirements:

(32 55 66 72 72 76) 77 (84 88 89 89 94 97)

4) 25th Percentile = Quartile 1 (Q1) which is the median of the first set of data

∴ 25th Percentile = (66+72)/2 = 138/2 = 69

5) 75th Percentile= Quartile 3 (Q3) which is the median of the second set of data

∴ 75th Percentile = (89+89)/2 = 89

6) Maximum = 97

7) Minimum = 32

8) Range = Maximum - Minimum = 97 - 32 = 65

9) IQR (interquartile range) = Q3 - Q1 = 89 - 69 = 20

7 0

4 years ago

The diameter of a circle is 14.2 kilometers. What is the circle's area?

strojnjashka [21]

Answer:

A ≈ 158.37km²

Step-by-step explanation:

Using the formulas

A=πr2

d=2r

Solving forA

A = 1 /4πd 2

= 1 /4·π·

14.22 ≈ 158.36769km²

Therefore, the are of the circle in nearest hundredth is A ≈ 158.37km²

4 0

3 years ago

7. Draw an equilateral triangle of side 6.5 cm and after locating its circumcentre. Draw its circumcircle. send it with image

mafiozo [28]

Answer:

Step-by-step explanation:

A circumcircle can be referred to as a circumscribed circle to a triangle. The steps to follow is stated below:

i. Since the triangle is equilateral, draw the triangle with sides 6.5 cm

ii. Bisect any of its two sides. The two bisecting lines would intersect at center, O, of the triangle.

iii. With the center and either radius OA, OB or OC, draw a circumscribed circle to the triangle.

The construction is attached to this answer for clarifications.

3 0

3 years ago