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3 years ago

7

What is the missing angle measure?

2 answers:

Reil [10]3 years ago

5 0

Answer:

33 degrees

Step-by-step explanation:

Because of the little square in the corner of the triangle, you know that that angle is 90 degrees. Since the second angle is 57 degrees and all of the interior angles of a triangle add up to 180 degrees, the final angle is 180-90-57=33 degrees. Hope this helps!

muminat3 years ago

4 0

Answer:

33

Step-by-step explanation:

the interior angle measure of all triangles is 180

you add the right and (90 degrees) to the 57 and subtract that from 180

this will get you 33

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Please help. How do I do this?

faltersainse [42]

One over three is the answer 1/3

8 0

3 years ago

Let C be the boundary of the region in the first quadrant bounded by the x-axis, a quarter-circle with radius 9, and the y-axis,

rewona [7]

Solution :

Along the edge $C_1$

The parametric equation for $C_1$ is given :

$x_1(t) = 9t , y_2(t) = 0 \ \ for \ \ 0 \leq t \leq 1$

Along edge $C_2$

The curve here is a quarter circle with the radius 9. Therefore, the parametric equation with the domain $0 \leq t \leq 1$ is then given by :

$x_2(t) = 9 \cos \left(\frac{\pi }{2}t\right)$

$y_2(t) = 9 \sin \left(\frac{\pi }{2}t\right)$

Along edge $C_3$

The parametric equation for $C_3$ is :

$x_1(t) = 0, \ \ \ y_2(t) = 9t \ \ \ for \ 0 \leq t \leq 1$

Now,

x = 9t, ⇒ dx = 9 dt

y = 0, ⇒ dy = 0

$\int_{C_{1}}y^2 x dx + x^2 y dy = \int_0^1 (0)(0)+(0)(0) = 0$

And

$x(t) = 9 \cos \left(\frac{\pi}{2}t\right) \Rightarrow dx = -\frac{7 \pi}{2} \sin \left(\frac{\pi}{2}t\right)$

$y(t) = 9 \sin \left(\frac{\pi}{2}t\right) \Rightarrow dy = -\frac{7 \pi}{2} \cos \left(\frac{\pi}{2}t\right)$

Then :

$\int_{C_1} y^2 x dx + x^2 y dy$

$=\int_0^1 \left[\left( 9 \sin \frac{\pi}{2}t\right)^2\left(9 \cos \frac{\pi}{2}t\right)\left(-\frac{7 \pi}{2} \sin \frac{\pi}{2}t dt\right) + \left( 9 \cos \frac{\pi}{2}t\right)^2\left(9 \sin \frac{\pi}{2}t\right)\left(\frac{7 \pi}{2} \cos \frac{\pi}{2}t dt\right) \right]$

$=\left[-9^4\ \frac{\cos^4\left(\frac{\pi}{2}t\right)}{\frac{\pi}{2}} -9^4\ \frac{\sin^4\left(\frac{\pi}{2}t\right)}{\frac{\pi}{2}} \right]_0^1$

= 0

And

x = 0, ⇒ dx = 0

y = 9 t, ⇒ dy = 9 dt

$\int_{C_3} y^2 x dx + x^2 y dy = \int_0^1 (0)(0)+(0)(0) = 0$

Therefore,

$\oint y^2xdx +x^2ydy = \int_{C_1} y^2 x dx + x^2 x dx+ \int_{C_2} y^2 x dx + x^2 x dx+ \int_{C_3} y^2 x dx + x^2 x dx$

= 0 + 0 + 0

Applying the Green's theorem

$x^2 +y^2 = 81 \Rightarrow x \pm \sqrt{81-y^2}$

$\int_C P dx + Q dy = \int \int_R\left(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y}\right) dx dy$

Here,

$P(x,y) = y^2x \Rightarrow \frac{\partial P}{\partial y} = 2xy$

$Q(x,y) = x^2y \Rightarrow \frac{\partial Q}{\partial x} = 2xy$

$\left(\frac{\partial Q}{\partial x}-\frac{\partial P}{\partial y} \right) = 2xy - 2xy = 0$

Therefore,

$\oint_Cy^2xdx+x^2ydy = \int_0^9 \int_0^{\sqrt{81-y^2}}0 \ dx dy$

$= \int_0^9 0\ dy = 0$

The vector field F is = $y^2 x \hat i+x^2 y \hat j$ is conservative.

5 0

3 years ago

An older TV screen was 26 centimeters wide. The newer model increased the screen size by 6 percent. How wide is the new TV Scree

Artist 52 [7]

Answer:

27.56 cm

Step-by-step explanation:

→ Identify the multiplier

( 100 + 6 ) ÷ 100 = 1.06

→ Multiply by the length

26 × 1.06 = 27.56

4 0

2 years ago

Read 2 more answers

Point M is the midpoint of AB. The coordinates of point A are (-8, 3) and the coordinates of M are (-2, 1). What are the coordin

ch4aika [34]

Answer:

the coordinates of point B are (-5, 2)

Step-by-step explanation:

1. use midpoint formula to find the midpoint (equation attached below)

2. plug in the numbers

$(\frac{-8+(-2)}{2},\frac{3+1}{2})$

3. solve

$(\frac{-8-2)}{2},\frac{3+1}{2})$

$(\frac{-10}{2},\frac{4}{2})$

$(-5,2})$

4 0

3 years ago

Devin is making a candle by pouring melted wax into a mold in the shape of a square pyramid. Each side of the base of the pyrami

Igoryamba

Answer:

5 cubes

Step-by-step explanation:

The volume of a square pyramid is given in terms of its side length (s) and height (h) as ...

V = (1/3)s^2·h

For the given measurements, the volume is ...

V = (1/3)(9 cm)^2 ·(10 cm) = 270 cm^3

___

The volume of each cube of wax is the product of its length, width, and height, so is ...

V = (4 cm)^3 = 64 cm^3

___

Then the number of wax cubes required to fill the pyramid is ...

(270 cm^3)/(64 cm^3/cube) = 4 7/32 cubes

Four cubes are not quite enough to make the candle.

Devin will need 5 cubes to make the candle.

3 0

3 years ago