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Ivenika [448]
3 years ago
8

Point M is the midpoint of AB. The coordinates of point A are (-8, 3) and the coordinates of M are (-2, 1). What are the coordin

ates of point B?
.
.
.
May you please show me the work?
Mathematics
1 answer:
ch4aika [34]3 years ago
4 0

Answer:

the coordinates of point B are (-5, 2)

Step-by-step explanation:

1. use midpoint formula to find the midpoint (equation attached below)

2. plug in the numbers

(\frac{-8+(-2)}{2},\frac{3+1}{2})

3. solve

(\frac{-8-2)}{2},\frac{3+1}{2})

(\frac{-10}{2},\frac{4}{2})

(-5,2})

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nadezda [96]

Answer:

The rate is  1 ÷ 2 yards per hour

Step-by-step explanation:

The computation of the rate does the amount of yarn changes is given below:

= 3 3 ÷ 4 - 1 1 ÷8

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= 21 ÷ 8 yards

 Now divide the above fraction by the number of hours

= 21 ÷ 8 yards ÷ 5 1 ÷ 4

= 21 ÷ 8 ×  4 ÷ 21

= 1 ÷ 2 yards per hour

Hence, the rate is  1 ÷ 2 yards per hour

The same would be relevant

8 0
3 years ago
What is the simplification of (-2x+4) + 2(2x+1)
melomori [17]
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4 0
3 years ago
99 POINT QUESTION, PLUS BRAINLIEST!!!
Basile [38]
1.Disc method.
In this method the volume is given by:

\boxed{V=\pi\int\limits_a^b\big[f(x)\big]^2}

so:

V=\pi\int\limits_1^3x^4\,dx=\boxed{\pi\int\limits_1^3\big[x^2\big]^2\,dx}

A) Function f(x)=x^2 over the interval [1,3]
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2. Shell method.

In this case volume is given by:

</span></span>\boxed{V=2\pi\int\limits_a^bx\cdot f(x)\,dx}

So there will be:

V=\pi\int\limits_1^3x^4\,dx=\dfrac{2}{2}\cdot\pi\int\limits_1^3x^4\,dx=2\pi\int\limits_1^3\dfrac{x^4}{2}\,dx=&#10;\boxed{2\pi\int\limits_1^3x\cdot\dfrac{x^3}{2}\,dx}

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3 0
3 years ago
Please help please☺
Lera25 [3.4K]
1. Felicia is 2 years old (2 cubed is 8)

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7 0
3 years ago
Read 2 more answers
Solve in radians help plz
PIT_PIT [208]
I think we can use the identity  sin x/2  = sqrt [(1 - cos x) /2]

cos x -  sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1

cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) =  cos x - 1   Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1

cos^2 x - 0.5 cos x - 0.5 = 0 

cos x = 1 , -0.5

giving x = 0 , 2pi, 2pi/3,  4pi/3  ( for  0  =< x <= 2pi)

because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.

The last 2 results dont fit so the answer is  x = 0 , 2pi Answer
5 0
3 years ago
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