Answer:
The rate is 1 ÷ 2 yards per hour
Step-by-step explanation:
The computation of the rate does the amount of yarn changes is given below:
= 3 3 ÷ 4 - 1 1 ÷8
= 15 ÷ 4 - 9 ÷ 8
= 21 ÷ 8 yards
Now divide the above fraction by the number of hours
= 21 ÷ 8 yards ÷ 5 1 ÷ 4
= 21 ÷ 8 × 4 ÷ 21
= 1 ÷ 2 yards per hour
Hence, the rate is 1 ÷ 2 yards per hour
The same would be relevant
(-2x+4)+2(2x+1)= -2(-x-3)
1.Disc method.
In this method the volume is given by:
![\boxed{V=\pi\int\limits_a^b\big[f(x)\big]^2}](https://tex.z-dn.net/?f=%5Cboxed%7BV%3D%5Cpi%5Cint%5Climits_a%5Eb%5Cbig%5Bf%28x%29%5Cbig%5D%5E2%7D)
so:
![V=\pi\int\limits_1^3x^4\,dx=\boxed{\pi\int\limits_1^3\big[x^2\big]^2\,dx}](https://tex.z-dn.net/?f=V%3D%5Cpi%5Cint%5Climits_1%5E3x%5E4%5C%2Cdx%3D%5Cboxed%7B%5Cpi%5Cint%5Climits_1%5E3%5Cbig%5Bx%5E2%5Cbig%5D%5E2%5C%2Cdx%7D)
A) Function

over the interval
![[1,3]](https://tex.z-dn.net/?f=%5B1%2C3%5D)
B) We use disk method and f(x) is function of variable x, so we <span>rotate the curve about the x-<span>axis.
2. Shell method.
In this case volume is given by:
</span></span>

So there will be:

A) Function

over the interval
![[1,3]](https://tex.z-dn.net/?f=%5B1%2C3%5D)
B) We use shell method and f(x) is function of variable x, so we <span>rotate the curve about the y-<span>axis.</span></span>
1. Felicia is 2 years old (2 cubed is 8)
2. If you take 288 times 3 and divide it by 4= 216
And 216 is a perfect cube
I think we can use the identity sin x/2 = sqrt [(1 - cos x) /2]
cos x - sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1
cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) = cos x - 1 Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1
cos^2 x - 0.5 cos x - 0.5 = 0
cos x = 1 , -0.5
giving x = 0 , 2pi, 2pi/3, 4pi/3 ( for 0 =< x <= 2pi)
because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.
The last 2 results dont fit so the answer is x = 0 , 2pi Answer