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ddd [48]
3 years ago
14

a President Bush international and 2005 the newspapers headlines started about four thousand million people in it in the newspap

er rounded to the nearest thousand and what what is the largest number in the smallest number of people who couldn't have been there

Mathematics
1 answer:
svlad2 [7]3 years ago
4 0
The smallest would be 400,000 and the largest would be the same because 0 can't round up or down
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Find the missing length. Round to the nearest tenth
Xelga [282]

Answer:

x ≈ 30.9 (Choice D)

Step-by-step explanation:

We can use cosine for solving this question:

cos (61°) = 15 / x

x = 15 / cos (61°)

x = 30.93998011

x ≈ 30.9 (Choice D)

7 0
3 years ago
Someone please help me!!!!11
serious [3.7K]
The U stands for union. Combine A and B


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4 0
3 years ago
The first three terms of an arithmetic series are 6p+2, 4p²-10 and 4p+3 respectively. Find the possible values of p. Calculate t
Doss [256]

Answer:

First Case:

\displaystyle p=\frac{5}{2}\text{ and } d=-2

Second Case:

\displaystyle p=-\frac{5}{4}\text{ and } d=\frac{7}{4}

Step-by-step explanation:

We know that the first three terms of an arithmetic series are:

6p+2, 4p^2-10, \text{ and } 4p+3

Since this is an arithmetic sequence, each subsequent term is <em>d</em> more than the previous term, where <em>d</em> is our common difference.

Therefore, we can write the second term as;

4p^2-10=(6p+2)+d

And, likewise, for the third term:

4p+3=(6p+2)+2d

Let's solve for <em>d</em> for each of the equations.

Subtracting in the first equation yields:

d=4p^2-6p-12

And for the second equation:

2d=-2p+1

To avoid fractions, let's multiply the first equation by 2. Hence:

2d=8p^2-12p-24

Therefore:

8p^2-12p-24=-2p+1

Simplifying yields:

8p^2-10p-25=0

Solve for <em>p</em>. We can factor:

8p^2+10p-20p-25=0

Factor:

2p(4p+5)-5(4p+5)=0

Grouping:

(2p-5)(4p+5)=0

Zero Product Property:

\displaystyle p_1=\frac{5}{2} \text{ or } p_2=-\frac{5}{4}

Then, we can use the second equation to solve for <em>d</em>. So:

2d_1=-2p_1+1

Substituting:

\begin{aligned} 2d_1&=-2(\frac{5}{2})+1 \\ 2d_1&=-5+1 \\ 2d_1&=-4 \\ d_1&=-2\end{aligned}

So, for the first case, <em>p</em> is 5/2 and <em>d</em> is -2.

Likewise, for the second case:

\begin{aligned} 2d_2&=-2(-\frac{5}{4})+1 \\ 2d_2&=\frac{5}{2}+1 \\ 2d_2&=\frac{7}{2} \\ d_2&=\frac{7}{4}\end{aligned}

So, for the second case, <em>p </em>is -5/4, and <em>d</em> is 7/4.

By using the values, we can determine our series.

For Case 1, we will have:

17, 15, 13.

For Case 2, we will have:

-11/2, -15/4, -2.

8 0
2 years ago
Helpie plz my teacher wont answer me
GaryK [48]

Answer:

45d + 42

Step-by-step explanation:

-7(-7d - 6) - 4d

49d + 42 - 4d

49d - 4d + 42

45d + 42

5 0
3 years ago
A proof in which you assume the opposite of what you want to prove is called what?
Taya2010 [7]
Proof<span> by contradiction........... </span>
4 0
3 years ago
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