Given: We have the given figure through which we can see
LK=16,
KJ=10,
LM=24,
MN=15
To Find: Whether KM || JN and the reasoning behind it.
Solution: Yes, KM || JN because 
Explanation:
For this solution, we use the concept of Similar Triangles.
Now, KM || JN if ΔLKM ~ ΔLJN (i.e., if ΔLKM is similar to ΔLJN).
Now, ∠MLK=∠NLJ
To prove similarity of the two triangles, we have to show that the sides are proportional. In other words, LK:KJ = LM:LN

which is true as both sides simplify to 
Thus, we see that ΔLKM ~ ΔLJN (i.e., if ΔLKM is similar to ΔLJN).
Therefore, KM || JN.
To come to the reasoning, notice that

In other words, 
Answer:
The correct answer is 108
Step-by-step explanation:
/
Thank me later.
7:50 am
60 minutes before 8:40 would be 7:40 so 10 minutes after that would be 7:50
Answer:
a) 30.726m/s and b) 5.5549s
Step-by-step explanation:
a.) What was Chris Huber’s speed in meters per second(m/s)?
Given the distance and time, the formula to obtain the speed is
.
Applying this to our problem we have that
.
So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.
b) What was Whittingham’s time through the 200 m?
In a) we stated that
. This formula implies that
.
First, observer that
.
Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, 
Then, applying 1) we have that

So, Sam Whittingham’s time through the 200 m was 5.5549s.