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USPshnik [31]
3 years ago
5

Given polynomials p, q, r, and s . q≠0 ,s≠0 and r≠0

Mathematics
1 answer:
kkurt [141]3 years ago
8 0

Answer:

\frac{p}{q} \div \frac{r}{s} = \frac{ps}{qr}

Step-by-step explanation:

Given

\frac{p}{q} \div \frac{r}{s} =

Required

Solve

\frac{p}{q} \div \frac{r}{s} =

Turn division to multiplication

\frac{p}{q} \div \frac{r}{s} = \frac{p}{q} * \frac{s}{r}

\frac{p}{q} \div \frac{r}{s} = \frac{ps}{qr}

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I have some questions regarding combinations in finite. Here is my first one I am stumped on:
podryga [215]

We will get the number of possible selections, and then subtract the number less than 25 cents.

We can choose the number of dimes 5 ways 0,1,2,3 or 4.
We can choose the number of nickels 4 ways 0,1,2 or 3.
We can choose the number of quarters 3 ways 0,1, or 2.

That's 5*4*3  = 60 selections 

Now we must subtract from the 60 the number of selections of coins that are less than 25 cents. These will involve only dimes and nickels. 

To get a selection of coin worth less than 25 cents:
If we use no dimes, we can use 0,1,2  on all 3 nickels.
That's 4 selections less than 25 cents. (that includes the choice of No coins at all in the 60, which we must subtract).

If we use exactly 1 dime , we can use 0,1,2, or all 3 nickels.
That's the 3 combinations less than 25 cents.

And there is 1 other selection less than 25 cents, 2 dimes and no nickels. 

So that's 4+3+1 = 8 selections which we must subtract from the 60.
 
Answer 60-8 = 52 selections of coins worth 25 cents or more.

8 0
3 years ago
I) Consider the following figure,<br><br> ​<br><br> ​<br><br> ​
qwelly [4]

Step-by-step explanation:

If PQRS is a quadrilateral inscribed in a circle, then the opposite angles of the quadrilateral are <u>supplementary</u><u>.</u>

y + 68° = 180° { being opposite angles of cyclic quadrilateral }

y = 180° - 68°

y = 112°

x + 82° = 180° { being opposite angles of cyclic quadrilateral }

x = 180° - 82°

x = 98°

Hope it will help :)❤

4 0
2 years ago
Is 38/58 in simplest form? Explain why or why not. If not, write it in simplest form
Fofino [41]

Both 38 and 58 are even so they both can be divided by 2,

38/58

19/29

that is in the simplest form

6 0
3 years ago
Read 2 more answers
What procedure will find the sum a+b of two numbers where a and b represent any integer?
ElenaW [278]

Answer:As rational number includes natural number, whole number ,integers  also.

⇒Natural number(1,2,3,4....) is a rational number also.

So, when A= Natural number , B=Any other natural number

Just add two natural number using simple law of addition.

⇒As Whole numbers(0,1,2,3,...) are Rational number also.

So If A=any whole number, B=Any other whole number

Add the whole number in any order using law of addition.

⇒Coming to integers (....-123,....-5,...-1,....12,....59,.....) By taking any two integers ,

1. Both of them are positive add using simple law of addition.

2. One of them is positive and other is negative , if larger one has positive sign before it just subtract smaller one from larger one and put positive sign before the result.and if larger one has negative sign before it ,subtract smaller one from larger one and put negative sign before the result.

⇒If both of them are negative , just add the two integers and apply negative sign before the result.

4. Rational number as fractions ,

A=m/n and B=p/q

A+B=m/n + p/q

find LCM of n and q.

If n and q are co-prime multiply n and q to get the LCM.For example if n=5, q=7, then LCM=5×7=35

If n and q are not co-prime find the factors of n and q .take out the common factors and then multiply the common factors with those factors which are not common.

For example, n=15, q=20

15=5×3

20=2×2×5

common factor=5

non common factor=2,2,3

LCM=5×2×2×3=60

Suppose LCM(n,q)= K

⇒p/q+m/n

=

So ,

which is the way to find LCM of rational number when theyare fractions.

Step-by-step explanation:

4 0
2 years ago
Imogene invested $8,000 in a bank account that pays 8 percent simple interest at the end of each year. Her friend invested the s
Natali5045456 [20]

The right system of equations to describe the situation would be on the form:

x1 = 8000 + y1*t

and

x2 = 8000 + y2*t

where x1 and x2 represents the total money of Imogene and her friend respectively at the end of t years.

Now for the value of amount earned, y1 and y2:

y1=8000*0.08

y2=2000*√(t-2)

<span> </span>

5 0
3 years ago
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