Answer:
The top left one.
Step-by-step explanation:
It would be the top left one since the graph starts at the 10 mark and 10 is the y intercept.
2 2/3 - 3/5
First, we can start by changing 2 2/3 to an improper fraction. To do this, we can use the rule: a b/c = ac+b/c. All we need to do is insert our numbers into the form of the rule.

Second, we can now start simplifying. (2 × 3 = 6 and 6 + 2 = 8).

Third, now we have change our denominators to be the same. To do this, we can start out by finding the least common denominator (LCD). List the multiples of both of the current denominators (3 and 5) and find the first common one.
Multiples of 3: 3, 6, 9, 12, 15
Multiples of 5: 5, 10, 15
Since 15 is our first common multiple, it is now our LCD.
Fourth, now we can multiply to change our denominators. Using our current denominators, we have to multiply by let's say (x / a variable). Basically, what can you multiply by 3 to get 15? That would be (3 × 5 = 15). For our other fraction, what would we multiply by 5 to get 15? (5 × 3 = 15). Remember, whatever you do to the bottom you must do to the top.

Fifth, we can now combine our denominators, which will make us have to add both of the numerators together.

Sixth, our last step is to convert the fraction into a mixed fraction. How you do this is to divide the numerator by the denominator. We would set up something like this: 31 ÷ 15 = 2.066667. That decimal in fraction form is 2 1/15, which is our answer.

Answer in fraction form:

Answer in decimal form:
Answer:
This is proved by ASA congruent rule.
Step-by-step explanation:
Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ
we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.
In ΔAPN and ΔAQL
∠PNA=∠ALQ (∵alternate angles)
AN=AL (∵diagonals of parallelogram bisect each other)
∠PAN=∠LAQ (∵vertically opposite angles)
∴ By ASA rule ΔAPN ≅ ΔAQL
Hence, by CPCT i.e Corresponding parts of congruent triangles PA=AQ
Hence, A is equidistant from LM and KN.
Answer:
alright if you give me brianliest on this, when you answer one of my questions ill give you brainliest. brailiest for a brianliest?
Step-by-step explanation: