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polet [3.4K]
3 years ago
6

Darrin is hanging 200 feet of Christmas garland on the fencing that encloses his rectangular front yard. The length is 5 feet le

ss than 5 times the width. Find the length and width of the fencing that encloses his rectangular front yard.
Mathematics
2 answers:
frutty [35]3 years ago
7 0

Answer:

Width = 17.5 feet,

Length = 82.5 feet.

Step-by-step explanation:

We have been given that Darrin is hanging 200 feet of Christmas garland on the fencing that encloses his rectangular front yard. This means that perimeter of rectangular front yard is 200 feet.

We know that perimeter of rectangle is two times the sum of length and width of rectangle. We can represent this information in an equation as:

2(l+w)=200...(1)

We are also told that the length is 5 feet less than 5 times the width. We can represent this information in an equation as:

l=5w-5...(2)

Upon substituting equation (2) in equation (1), we will get:

2(5w-5+w)=200

2(6w-5)=200

12w-10=200

12w-10+10=200+10

12w=210

\frac{12w}{12}=\frac{210}{12}

w=17.5

Therefore, the width of rectangular front is 17.5 feet.

Upon substituting w=17.5 in equation (2), we will get:

l=5(17.5)-5

l=87.5-5

l=82.5

Therefore, the length of rectangular front is 82.5 feet.

svetlana [45]3 years ago
5 0

Answer:

Width = 17.5 feet and length= 82.5 feet

Step-by-step explanation:

Let w be the width of the rectangular front yard.

It is given that the length is 5 feet less than 5 times the width.

l=5w-5

The perimeter of a rectangle is

Perimeter=2(l+w)

Perimeter of rectangular front yard is

Perimeter=2(5w-5+w)

Perimeter=2(6w-5)

Perimeter=12w-10           .... (1)

Darrin is hanging 200 feet of Christmas garland on the fencing that encloses his rectangular front yard.

Perimeter=200           .... (2)

From (1) and (2) we get

12w-10=200

Add 10 on both sides.

12w=200+10

12w=210

Divide both sides by 12.

w=\frac{210}{12}

w=17.5

Therefore, the width of the rectangular yard is 17.5 feet.

l=5w-5

Substitute w=17.5.

l=5(17.5)-5

l=87.5-5

l=82.5

Therefore, the length of the rectangular yard is 82.5 feet.

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