A light bulb consumes 960 watt-hours per day. How many watt-hours does it consume in

-3•f(-8)+7•g(2)=??????????

jolli1 [7]

Answer:

-22

Step-by-step explanation:

-3•f(-8)+7•g(2)=

The value of f(x) at x=-8 is

f(-8) = -2

The value of g(x) at x=2 is

g(2) = -4

Substituting these values into the equations

-3 * -2 +7*-4

6 -28

-22

5 0

3 years ago

Read 2 more answers

Given that a = 24 cm and b = 7 cm, work out x

Fiesta28 [93]

X = 25cm , i used pythagoras theorem to calculate this, 7^2 + 24^2 = 625, the square root of 625 = 25

3 0

3 years ago

Mrs. Robinson, an insurance agent, earns a salary of $4,800 per year plus a 3% commission on her sales. The average price of a p

nekit [7.7K]

Answer:

Required inequality is $4800+183x>8000$ .

Step-by-step explanation:

Given that Mrs. Robinson, an insurance agent, earns a salary of $4,800 per year plus a 3% commission on her sales. The average price of a policy she sells is $6,100. Write an inequality to find how many policies Mrs. Robinson must sell to make an annual income of at least $8,000.

Calculation is given by:

Salary per year = $4,800

Average price of a policy = $6,100.

commission on her sales = 3%

Then commission on $6,100 = 3% of $6,100 = 0.03 ($6,100) = $183

Let number of policies Mrs. Robinson must sell to make an annual income of at least $8,000 = x

then total commission on x policies = 183x

Total income using x policies = 4800+183x

Since she wants to make an annual income of at least $8,000. so we can write inequality as:

$4800+183x>8000$

Hence required inequality is $4800+183x>8000$ .

5 0

3 years ago

A number when divided by 780 gives remainder 38 .What

baherus [9]

Given:

A number when divided by 780 gives remainder 38.

To find:

The reminder that would be obtained by dividing same number by 26.

Solution:

According to Euclis' division algorithm,

$a=bq+r$ ...(i)

Where, q is quotient and $0\leq r$ is the remainder.

It is given that a number when divided by 780 gives remainder 38.

Substituting $b=780,\ r=38$ in (i), we get

$a=(780)q+38$

So, given number is in the form of $780q+38$ , where q is an integer.

On dividing $780q+38$ by 26, we get

$\dfrac{780q+38}{26}=\dfrac{780q}{26}+\dfrac{38}{26}$

$\dfrac{780q+38}{26}=30q+\dfrac{26+12}{26}$

$\dfrac{780q+38}{26}=30q+\dfrac{26}{26}+\dfrac{12}{26}$

$\dfrac{780q+38}{26}=30q+1+\dfrac{12}{26}$

Since q is an integer, therefore (30q+1) is also an integer but $\dfrac{12}{26}$ is not an integer. Here 26 is divisor and 12 is remainder.

Therefore, the required remainder is 12.

4 0

2 years ago

The measurenicnt of the circumference of a circle is found to be 56 centimeters. The possible error in measuring the circumferen

BartSMP [9]

Answer:

(a) Approximate the percent error in computing the area of the circle: 4.5%

(b) Estimate the maximum allowable percent error in measuring the circumference if the error in computing the area cannot exceed 3%: 0.6 cm

Step-by-step explanation:

(a)

First we need to calculate the radius from the circumference:

$c=2\pi r\\r=\frac{c}{2\pi } \\c=8.9 cm$

I leave only one decimal as we need to keep significative figures

Now we proceed to calculate the error for the radius:

$\Delta r=\frac{dt}{dc} \Delta c\\\\\frac{dt}{dc} = \frac{1}{2 \pi } \\\\\Delta r=\frac{1}{2 \pi } (1.2)\\\\\Delta r= 0.2 cm$

$r = 8.9 \pm 0.2 cm$

Again only one decimal because the significative figures

Now that we have the radius, we can calculate the area and the error:

$A=\pi r^{2}\\A=249 cm^{2}$

Then we calculate the error:

$\Delta A= (\frac{dA}{dr} ) \Delta r\\\\\Delta A= 2\pi r \Delta r\\\\\Delta A= 11.2 cm^{2}$

$A=249 \pm 11.2 cm^{2}$

Now we proceed to calculate the percent error:

$\%e =\frac{\Delta A}{A} *100\\\\\%e =\frac{11.2}{249} *100\\\\\%e =4.5\%$

(b)

With the previous values and equations, now we set our error in 3%, so we just go back changing the values:

$\%e =\frac{\Delta A}{A} *100\\\\3\%=\frac{\Delta A}{249} *100\\\\\Delta A =7.5 cm^{2}$

Now we calculate the error for the radius:

$\Delta r= \frac{\Delta A}{2 \pi r}\\\\\Delta r= \frac{7.5}{2 \pi 8.9}\\\\\Delta r= 0.1 cm$

Now we proceed with the error for the circumference:

$\Delta c= \frac{\Delta r}{\frac{1}{2\pi }} = 2\pi \Delta r\\\\\Delta c= 2\pi 0.1\\\\\Delta c= 0.6 cm$

5 0

3 years ago