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Hoochie [10]
3 years ago
6

A page break can be prevented from being added before or after a heading by using the keyword _____ in the page-break-before or

page-break-after properties.
Computers and Technology
1 answer:
Sedaia [141]3 years ago
3 0

Answer:

avoid

Explanation:

<h2><u>Fill in the blank </u></h2>

A page break can be prevented from being added before or after a heading by using the keyword <u>avoid</u>  in the page-break-before or page-break-after properties.

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Please conduct some research and find an article on Security Threats and please provide link of the article.
finlep [7]

Answer:

There are Security Threats happening every other day in the world. Some are minor while others can catastrophic.

Explanation:

There are also many types of <u>Security Threats</u>, <u>Breaches</u>, and <u>Hacks</u> in the world of IT. Each with their own Security Measures. Below are two links about this topic. The first link is an article about 5 of the worst corporate Security Breaches/Hacks to have taken place. While the second link is an article about the Top 10 Network Security Threats.

https://abcnews.go.com/Technology/marriotts-data-breach-large-largest-worst-corporate-hacks/story?id=59520391

https://securitytrails.com/blog/top-10-common-network-security-threats-explained

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

5 0
3 years ago
Weak Induction
slega [8]

Answer:

Following are the answer to this question:

Explanation:

In option 1:

The value of n is= 7, which is (base case)

\to 3^7

when n=k for the true condition:

\to 3^k

when n=k+1 it tests the value:

\to 3^{(k+1)}= 3^k,3\\\to < (k!) 3 \ substituting \ equation \\\to

since k>6  hence the value is KH>3 hence proved.

In option 2:

when:

for n=1:(base case)

\log(1!)

0<=0 \\ condition is true

when the above statement holds value n=1

when n=k

\log(k!)

when n=k+1

\log(k+1)!=\log(k!)+\log(k+1)\\

             

\because k \log k      [\therefore KH>K \Rightarrow  \log(KH>\loK)]

In option 3:

when n=1:

A_1 \cup B=A_1 \cup B\\\\

when n=k

\to (A_1\cap A_2 \cap.....A_k) \cup B\\=(A_1\cup B) \cap(A_2\cup B_2)....(A_k \capB).....(a)\\\to n= k+1\\ \to (A_1\cap A_2 \cap.....A_{kH}) \cup B= (A_1\cup B)\\\\\to  [(A_1\cap A_2 \cap.....A_{k}) \cup B]\cap (A_{KH}\cup B)\\\\\to  [(A_1\cup B) \cap (A_2 \cup B) \cap (A_3\cup B).....(A_k\cup B)\cap (A_{k+1} \cup B)\\\\  \ \ \ \ \ \ substituting \ equation \ a \\\\

hence n=k+1 is true.

7 0
3 years ago
How do I mirror cast my smart lg tv?​
lora16 [44]
I really wish I could help you but I don’t know
6 0
3 years ago
What does xhtml stand for?
igomit [66]
Extensible Hypertext Markup Language.
3 0
3 years ago
Read 2 more answers
The action in which a router divides and forwards incoming or outbound message traffic to multiple links is known as
kipiarov [429]
Load balancing is my best guess.
5 0
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