All categories

3 years ago

The equation of a line is x + 5y = 12.

Mathematics

1 answer:

Svet_ta [14]3 years ago

4 0

Answer: C: 12/5

Step-by-step explanation:

y intercept is where x is 0, so set x equal to 0

0+5y=12

y=12/5

You might be interested in

Judy can decorate 3 cakes in 5 hours. Which graph represents this same rate?

mojhsa [17]

Answer:

The first one with the pink background

Step-by-step explanation:

It's the only one that matches perfectly

3 0

3 years ago

Read 2 more answers

P=(2s + 4)+ (3s + 1)

skad [1K]

Since there is an addition symbol in the middle all you need to do is combine like terms/add. Your final answer should be:
p= 5s+5

3 0

3 years ago

-4 < -2x + 4 <12<br> How do you solve this compound inequality

Lelechka [254]

Answer:

can you explain it more clear? ;)

Step-by-step explanation:

3 0

4 years ago

Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.

Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{1599\text{ years}}$

$k=4.33\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 1000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=5.19g$

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 10000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=0.105g$

Thus, the amount after 10000 years will be, 0.105 grams.

4 0

4 years ago

What is the ratio of 120%

Helga [31]

Answer:

5: 6

Step-by-step explanation:

becuase it was basically 100:120 but divide it by 20 and thats how you get 5;6

7 0

3 years ago