Answer:
You can open the version of your computer or device from the task manager to see the running programs and close the application
Explanation:
Right-click on the Windows Start menu and choose Task Manager (another way to open it is to press the keyboard shortcut Ctrl + Alt + Delete and select it from the options that appear).
NOTE: Click here if you don't know how to display Windows 8 Start.
You will see the main Administrator window (as in the image above). Displays a list of the programs that are currently running.
Find the application or process you want to close. Click on it with the RIGHT button and choose End task. In some cases a notice appears asking you to confirm it. Read what it says to know the consequences of forcing it. Confirm if you are determined to do so.
IMPORTANT:
There are viruses, adware or other spam programs that you may not be able to close even in this way. For these cases follow this link on how to clean viruses without entering Windows.
When you're done you can exit the Task Manager window. Click here to close background applications.
Estos pasos sirven para forzar que se cierren programas que no responden en Windows 10, 8 u 8.1. Enlazan además a instrucciones para cerrar programas o aplicaciones
The simulation, player 2 will always play according to the same strategy.
Method getPlayer2Move below is completed by assigning the correct value to result to be returned.
Explanation:
- You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.
#include <bits/stdc++.h>
using namespace std;
bool getplayer2move(int x, int y, int n)
{
int dp[n + 1];
dp[0] = false;
dp[1] = true;
for (int i = 2; i <= n; i++) {
if (i - 1 >= 0 and !dp[i - 1])
dp[i] = true;
else if (i - x >= 0 and !dp[i - x])
dp[i] = true;
else if (i - y >= 0 and !dp[i - y])
dp[i] = true;
else
dp[i] = false;
}
return dp[n];
}
int main()
{
int x = 3, y = 4, n = 5;
if (findWinner(x, y, n))
cout << 'A';
else
cout << 'B';
return 0;
}
Answer:
it is called a dotted half note
