9.4 Code Practice: Your task is to determine whether each item in the array above is divisible
1 answer:
Answer:
Explanation:
The following Python code is a function that takes in an array as a parameter, it then loops through the array determining if the element is divisible by 3. If it is it leaves it alone, otherwise it changes it to a 0. Then ouputs the array. A test case is shown in the attached image below using a sample array.
def divisible_by_three(array):
for x in array:
if x % 3 == 0:
pass
else:
array[array.index(x)] = 0
return array
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Answer:
Explanation:
Solving (a): To base 10
We simply multiply each digit by a base of 16 to the power of their position.
i.e.
In hexadecimal
So:
This gives:
In hexadecimal
So:
Solving (b): To base 10
We simply multiply each digit by a base of 2 to the power of their position.
i.e.
Solving (c): To base 16
First, convert to base 10
In (b)
Next, is to divide 781754 by 16 and keep track of the remainder
Write out the remainder from bottom to top
In hexadecimal
So:
In b
Next, is to divide 11057389 by 16 and keep track of the remainder
Write out the remainder from bottom to top
In hexadecimal
So:
Solving (d): To octal
Divide 74510 by 8 and keep track of the remainder
Write out the remainder from bottom to top
Divide 67210 by 8 and keep track of the remainder
Write out the remainder from bottom to top