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ExtremeBDS [4]
3 years ago
14

Consider a circle whose size can vary. The circumference of the circle is always 2 π 2π times as large as its radius. Let r r re

present the radius of the circle (in feet) and let C C represent the circumference of the circle (in feet). Write a formula that expresses C C in terms of r r. Preview
Mathematics
1 answer:
Alenkasestr [34]3 years ago
4 0

Answer: C=2\pi r

Step-by-step explanation:

Let be "C" the circumference of the circle (in feet) and "r" the radius of the circle (in feet).

Based on the information provided in the problem, you know that the circumference of the circle is always 2\pi as large as its radius.

Notice that this indicates a multiplication. Then, this means that the circumference of the circle is always equal to 2\pi by "r".

Based on this, you can write the following formula that expresses the circumference "C" in terms of the radius "r":

C=2\pi r

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I have no clue what do you, can someone please explain
fiasKO [112]

Answer:

a = 3   b = -18   c = 11   d = 0

Step-by-step explanation:

The table tells you what value the function will product (y) if you input the corresponding value of x.

So, for example, if you input the value of x = 1 into the function, you will get y = -4.

If we substitute x = 0 and y = 0 into the function we can find the value of d immediately:

0 = a(0)³ + b(0)² +c(0) + d

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0 = d

As d = 0, we can now eliminate d and write the function as:

y = ax³ + bx² + cx

Now substitute the remaining pairs of values into y = ax³ + bx² + cx to create 3 equations:

1) When x = 1, y = -4

⇒ a(1)³ + b(1)² + c(1) = -4

⇒ a + b + c = -4

2) When x = 2, y = -26

⇒ a(2)³ + b(2)² + c(2) = -26

⇒  8a + 4b + 2c = -26

⇒  4a + 2b + c = -13

3) When x = 3, y = -48

⇒ a(3)³ + b(3)² + c(3) = -48

⇒ 27a + 9b + 3c = -48

⇒ 9a + 3b + c = -16

Now solve the system of 3 equations simultaneously to find the value of a, b and c.  To do this, reduce this to 2 equations with 2 unknowns by eliminating one of the unknowns from two pairs of equations:

Eliminate c by subtracting equation 1) from equation 2) to create equation 4):

2)  4a + 2b + c = -13

1)   a + b + c = -4

4)  3a + b = -9

Eliminate c by subtracting equation 2) from equation 3) to create equation 5):

3)  9a + 3b + c = -16

2)  4a + 2b + c = -13

5)  5a + b = -3

Now use equations 4) and 5) to find a and b, by subtracting equation 4) from equation 5) to find a:

5)  5a + b = -3

4)  3a + b = -9

6)  2a = 6

  ⇒  a = 6 ÷ 2 = 3

and substituting the found value of a into equation 4) or 5) to find b:

5)  5(3) + b = -3

      15 + b = -3

         ⇒ b = -18

Now substitute the found values for a and b into one of the original 3 equations to find c:

1)   a + b + c = -4

    3 - 18 + c = -4

              ⇒ c = 11

Therefore,  the function is   y = 3x³ - 18x² + 11x

3 0
3 years ago
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