Answer:
The probability of selecting at least one consonant when selecting 2 cards is 0.0954.
Step-by-step explanation:
There are 26 letters in the English alphabet series.
Of these 26 letters there are 5 vowels and 21 consonants.
The total number of ways to select 2 letters is:
The number of ways to select at least one consonant is:
n (At least 1 consonant) = N - n (Two vowels)
Compute the probability of selecting at least one consonant as follows:
Thus, the probability of selecting at least one consonant when selecting 2 cards is 0.0954.
Answer:
Step-by-step explanation:
Answer:
y=3x-6
Step-by-step explanation:
use 2 of the points for y=a×x+b
we use (2,0) and (3,3) as an example
we get
0=2a+b & 3=3a+b
so
3-0=3a+b-(2a+b)
3=a
b=-6
<span>The first 5 multiples of 18 are 18,36,54,72,90
</span><span>The factors of 18 are 1,2,3,6,9, and 18. </span>