19 6/7 divided by 4 1/8

3) What is the shape of the graph of the equation y = 5x – 2?

german

Answer:

Line

Step-by-step explanation:

The equation y = 5x - 2 is slope-intercept form of linear function.

The shape of the graph is the line

It has positive slope of 5, therefore is increasing function, the line goes up from left to right on the coordinate plane

6 0

3 years ago

Find the percent of decrease from 270 to 200. Round to the nearest 10th of a percent if necessary.

choli [55]

270-200 = 70

70/200 = 0.35 = 3.5%

3 0

3 years ago

X+2y-z = 9<br> -2x+y+z= 1<br> 2x-y+2z= -5

hodyreva [135]

Answer:

I don't understand the first one

7 0

3 years ago

ANSWER I ADDED EXTRA POINTS BUT ANSWER RIGHT AND EXPLAIN YOUR ANSWER!!!! 2 QUESTIONS...

Sophie [7]

Answer:

24) D

25) D

Step-by-step explanation:

24) D

We want to find the equation of a line (in slope-intercept form) that passes through (2, -2) and is perpendicular to $y=\frac{2}{5}x+2$ .

First, let's find the slope of our new line.

Remember that perpendicular slopes are negative reciprocals of each other.

Therefore, to find the slope of our new line, we will flip our old slope and add a negative.

Therefore, the slope of our new line is -5/2.

Now, we can use the point-slope form:

$y-y_1=m(x-x_1)$

Where m is the slope and (x₁, y₁) is a point.

So, let's substitute -5/2 for our slope and (2, -2) for our point (x₁, y₁). This yields:

$y-(-2)=-\frac{5}{2}(x-2)$

Simplify:

$y+2=-\frac{5}{2}(x-2)$

Let's convert this to slope-intercept form. Distribute the right:

$y+2=-\frac{5}{2}x+5$

Subtract 2 from both sides. So, our equation is:

$y=-\frac{5}{2}x+3$

Our answer is D.

25)

We know that the cost for buying x items is given by the function:

$C(x)=6x$

We also know that the items are sold in packages of 10 only. And no one can buy more than 5 packages. In other words, we can buy 0, 1, 2, 3, 4, or 5 packages.

So, let's see how much it will be if we buy 0 packages. This will just be:

$C(0)=6(0)=\$0$

If we buy 1 package, there will be 10 items in them. So:

$C(10)=6(10)=\$60$

If we do this for 2 packages (20 items), 3 packages (30 items), and so on, we will get:

$C(20)=6(20)=\$120\\C(30)=6(30)=\$180\\C(40)=6(40)=\$240\\C(50)=6(50)=\$300$

So, our range is:

$\{0, 60, 120, 180, 240, 300\}$

The correct answer is D.

And we're done!

4 0

3 years ago

find the value of "a" and "b" for which the limit exists both as x approaches 1 and as x approaches 2:

lbvjy [14]

Answer:

a = 4

b = -2

Step-by-step explanation:

If the given function is continuous at x = 1

$\lim_{x \to 1^{-}} f(x)=(x+1)$

$=2$

$\lim_{x \to 1^{+}} f(x)=ax+b$

$=a+b$

$\lim_{x \to 1} f(x)=ax+b$

$=a+b$

And for the continuity of the function at x = 1,

$\lim_{x \to 1^{-}} f(x)=\lim_{x \to 1^{+}} f(x)=\lim_{x \to 1} f(x)$

Therefore, (a + b) = 2 -------(1)

If the function 'f' is continuous at x = 2,

$\lim_{x \to 2^{-}} f(x)=ax+b$

$=2a+b$

$\lim_{x \to 2^{+}} f(x)=3x$

$=6$

$\lim_{x \to 2} f(x)=3x$

$=6$

Therefore, $\lim_{x \to 2^{-}} f(x)=\lim_{x \to 2^{+}} f(x)=\lim_{x \to 2} f(x)$

2a + b = 6 -----(2)

Subtract equation (1) from (2),

(2a + b) - (a + b) = 6 - 2

a = 4

From equation (1),

4 + b = 2

b = -2

3 0

3 years ago