First angle in the triangle is 52 degrees Celsius and I need to find the outside and top
1 answer:
In figure,
AC = BC (given)
Since, in a triangle , angles opposite to equal sides are also equal.
Therefore,
b= 52°
Now,
°.° c is exterior angle of triangle.
.°. c = b + 52°
=> c = 52° + 52°
=> c = 104°
Solution:-
-------------
b = 52° & c =104°
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