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2 years ago

Find the mean (average) of the data set below? 2/4, 18/5, 28/10, 5/20

Mathematics

1 answer:

laila [671]2 years ago

6 0

the mean (average) of the data set below

2/4, 18/5, 28/10, 5/20

We are given with 4 fraction

to find mean , we add all the fractions and divide by 4

Lets add all the fractions

$\frac{2}{4} + \frac{18}{5} + \frac{28}{10} + \frac{5}{20}$

Make the denominators same

LCM is 20

Try to get 20 in the denominator

$\frac{2*5}{4*5} + \frac{18*4}{5*4} + \frac{28*2}{10*2} + \frac{5}{20}$

$\frac{10}{20} + \frac{72}{20} + \frac{56}{20} + \frac{5}{20}$

$\frac{143}{20}$

Now we divide by 4

$\frac{\frac{143}{20}}{4}=\frac{143}{80}=1\frac{63}{80}$

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Solve the equation by clearing the decimals: 0.8x -0.3 = 0.7x + 0.2

Mashutka [201]

Answer:

x = 5

Step-by-step explanation:

0.8x - 0.3 - 0.7x = 0.2

0.8x - 0.7x = 0.2 + 0.3

0.1x = 0.2 + 0.3

0.1x = 0.5

5 0

3 years ago

I’m trying to correct this problem but I don’t know how can someone help me

BartSMP [9]

Remark

It is not a straight line distance from the park to the mall. None of the answers give you that result. And if you know what displacement is, none of the answers are really displacement either. The distance is sort of a "as the crow flies." distance. There's a stop off in the middle of town.

Method

You need to use the Pythagorean Formula twice -- once from the park to the city Center and once from the city center to the mall.

Distance from the Park to the city center.

a = 3 [distance east]

b = 4 [distance south]

c = ??

c^2 = 3^2 + 4^2 Take the square root of both sides.

c = sqrt(3^2 + 4^2)

c = sqrt(9 + 16) Add

c = sqrt(25)

c = 5

So the distance from the park to the city center is 5 miles

Distance from City center to the mall

a = 2 miles [distance east]

b = 2 miles [distance north]

c = ??

c^2 = a^2 + b^2 Substitute

c^2 = 2^2 + 2^2 Expand this.

c^2 = 4 + 4

c^2 = 8 Take the square root of both sides.

sqrt(c^2) = sqrt(8)

c = sqrt(8) This is the result

c = 2.8

Answer

Total distance = 5 + 2.8 = 7.8

6 0

3 years ago

company with a large fleet of cars hopes to keep gasoline costs down and sets a goal of attaining a fleet average of at least 26

podryga [215]

Answer:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

$p_v =P(t_{(49)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

Step-by-step explanation:

Data given and notation

$\bar X=25.02$ represent the sample mean

$s=4.83$ represent the sample standard deviation

$n=50$ sample size

$\mu_o =26$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is at least 26 mpg, the system of hypothesis would be:

Null hypothesis: $\mu \geq 26$

Alternative hypothesis: $\mu < 26$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=50-1=49$

Since is a one sided test the p value would be:

$p_v =P(t_{(49)}$

Conclusion

3 0

3 years ago

What is the square root of -372

wel

Answer:

19.2873015 (Done by a calculator) <---- could be wrong

Step-by-step explanation:

And fun fact:

Negative numbers don't have real square roots since a square is either positive or 0. The square roots of numbers that are not perfect square are members of irrational numbers. This means that they can't be written as the quotient of two integers.

Hope it helps!

4 0

2 years ago

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Write the next three terms in each sequence. Make sure your

vazorg [7]

Um, wouldn’t it just be 9.5, 10.6, 11.7?

8 0

3 years ago

Read 2 more answers