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Alecsey [184]
3 years ago
13

Ter.

Mathematics
1 answer:
quester [9]3 years ago
4 0

Answer:

commutative property

Step-by-step explanation:

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Please tell me the outlier of each set of numbers (3 sets only)!
yulyashka [42]

Hey there!

An outlier in a data set is a number that is WAY larger or WAY smaller than the others in the data set, or does not really fit in the specified "range". In the first one, 452 is way greater than everything else, so it would be the outlier.

In the second data set, 5 would be our outlier because it is much smaller than all the other numbers.

In the last data set, the numbers are pretty close together, but we need to find one that isn't inside the small range. 0.201 appears to be the outlier in this case.

Therefore, here are your answers :)

15: 452

16: 5

17: 0.201

I hope this helps!

5 0
3 years ago
For the graph below, what should the domain be so that the function is at least 300?
tatiyna
Y = -2x^2 + 50x + 300
-2x^2 + 50x + 300 ≥ 300
-2x^2 + 50x ≥ 0
-2x^2 ≥ -50x
x^2 ≤ 25x
x ≤ 25

Therefore, required domain is 0 ≤ x ≤ 25
4 0
3 years ago
Read 2 more answers
I know that it falls to the left and rises to the right but how do I express that here?
Jlenok [28]

Answer:

c

Step-by-step explanation:

4 0
3 years ago
1. 2x-3=5+2x 2. 7b-6(1-2b)=10. 3. 8z+12=5z-21
dexar [7]
1. x is indefine

2. b= 16/19

3. z= -11

4. k= 23/20

5. x= 0
7 0
3 years ago
The size 4 soccer ball Sean’s team uses should weigh no more than 0.37 kilograms, and no less than 0.31 kilograms. A soccer bag
dmitriy555 [2]

Answers:

Q: What is the most they could weigh together?

A:  0.74 kg

-----

Q: What is the least they could weigh together?

A:  0.62 kg

=================================================

Work Shown:

x = weight of first ball

y = weight of second ball

each ball has a weight range of 0.31 kg to 0.37 kg, so,

0.31 \le x \le 0.37

0.31 \le y \le 0.37

add straight down to get

0.31+0.31 \le x+y \le 0.37+0.37

which simplifies to

0.62 \le x+y \le 0.74

the two soccer balls have a weight range of 0.62 to 0.74, inclusive of both endpoints.

--------

Without using algebra, you basically just add the smallest the two weights could be (0.31) to itself to get 0.31+0.31 = 0.62 which represents the smallest the two weights combined can be. The same happens with the largest weight of 0.37 to get 0.37+0.37 = 0.74 as the max weight of both objects together.

7 0
4 years ago
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