All categories

3 years ago

Dicriminant of x² – 49 = 0

Mathematics

1 answer:

Mama L [17]3 years ago

6 0

Answer:

196

Step-by-step explanation:

The discriminant (Δ) is given by:

$\Delta = b^2-4ac$

Where the polynomial is in the form:

$ax^2+bx+c=0$

In this problem, a = 1, b = 0, and c = -49. Thus, plugging it into the formula:

$\Delta = 0^2-4(1)(-49) = -(-196) = 196$

Thus, the discriminant of x² – 49 = 0 is 196.

You might be interested in

A zucchini plant in Darnell’s garden was 12 centimeters tall when it was first planted. Since then, it has grown approximately 0

Andrews [41]

A) 12 + 0.5d d=day
b) 0.195/0.5=0.39d

5 0

3 years ago

Read 2 more answers

Help me please lol !!!!!

STatiana [176]

Answer:

Step-by-step explanation:

8 0

3 years ago

How many different ways are there to choose a subset of the set {1,2,3,4,5,6} so that the product of the members of the subset i

zvonat [6]

You have to pick at least one even factor from the set to make an even product.

There are 3 even numbers to choose from, and we can pick up to 3 additional odd numbers.

For example, if we pick out 1 even number and 2 odd numbers, this can be done in

$\dbinom 31 \dbinom 32 = 3\cdot3 = 9$

ways. If we pick out 3 even numbers and 0 odd numbers, this can be done in

$\dbinom 33 \dbinom 30 = 1\cdot1 = 1$

way.

The total count is then the sum of all possible selections with at least 1 even number and between 0 and 3 odd numbers.

$\displaystyle \sum_{e=1}^3 \binom 3e \sum_{o=0}^3 \binom 3o = 2^3 \sum_{e=1}^3 \binom3e = 8 \left(\sum_{e=0}^3 \binom3e - \binom30\right) = 8(2^3 - 1) = \boxed{56}$

where we use the binomial identity

$\displaystyle \sum_{k=0}^n \binom nk = \sum_{k=0}^n \binom nk 1^{n-k} 1^k = (1+1)^n = 2^n$

3 0

1 year ago

The graph represents the speed at which Pete's marble travels.

fiasKO [112]

Answer:b

Step-by-step explanation:

5 0

3 years ago

Is it possible for a composite number to have more than one prime factorization? Is it possible for a number to have no prime fa

Nitella [24]

Prime factors are factors of a composite number that are indivisible except by the number 1 or the number itself. The answers to your questions are the following:

1. Yes, it is possible especially for very large numbers.
2&3. No, because as mentioned previously, the default prime factors of numbers are 1 and the number itself. For example, 2 is a prime number. Its factors are 1 and 2.
4. Prime factorization are useful in fields of encryption. They make use of the basic prime numbers for the arithmetic modulus with the general equation: n=pq.

3 0

4 years ago