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jarptica [38.1K]
3 years ago
8

Given the directed line segment from A to B, construct the point P that divides the segment in the ratio 4 to 3 from A to B.

Mathematics
1 answer:
Naddik [55]3 years ago
7 0

Answer:

Figure D is the construction of point P which divides the segment in the ratio 4 to 3 from A to B.

Step-by-step explanation:

To prove that point P divides the segment AB in the ratio 4 to 3, find the figure which divided into 7 equal parts and the number of parts from A to P is 4 and the number of parts from P to B is 3

Let us check each answer

Answer A:

∵ AB is divided into 7 equal parts

∵ The number of parts from A to P is 1

∵ The number of parts from P to B is 6

∴ P divides AB in the ratio 1 to 6 from A to B

Answer B:

∵ AB is divided into 7 equal parts

∵ The number of parts from A to P is 2

∵ The number of parts from P to B is 5

∴ P divides AB in the ratio 2 to 5 from A to B

Answer C:

∵ AB is divided into 7 equal parts

∵ The number of parts from A to P is 3

∵ The number of parts from P to B is 4

∴ P divides AB in the ratio 3 to 4 from A to B

Answer D:

∵ AB is divided into 7 equal parts

∵ The number of parts from A to P is 4

∵ The number of parts from P to B is 3

∴ P divides AB in the ratio 4 to 3 from A to B

Figure D is the construction of point P that divides the segment in the ratio 4 to 3 from A to B.

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