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3 years ago

I'll give brainlist for this !!!!!!!!

Mathematics

1 answer:

castortr0y [4]3 years ago

4 0

Answer:

The first error in the bill is +8

because when two opposite signs of number are multiplied so the result is always negative.

so,

2 × -4 = -8

instead of 8 their should be -8.

hope this answer helps you dear...take care!

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Find the slope of the line which goes through the given points.<br> d<br> A(2,8) and B(2,6)

KATRIN_1 [288]

Answer:

Undefined

Step-by-step explanation:

A slope is found using the formula rise (change in y) over run (change in x). The change in x is 0, and the change in y is -2. The answer is -2/0, but dividing by 0 gives you undefined. Don't believe me? Look at the attached image.

Hope this helps!

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3 years ago

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A chef got 7 bags of onions. The red onions came in bags of 8 and the yellow onions came in bags of 3. If the chef got a total o

frutty [35]

Answer:

$\#\text{ of 8-onion bags: }4,\\\#\text{ of 3-onion bags: }3$

Step-by-step explanation:

Let $a$ be the number of bags with 8 onions and let $b$ be the number of bags with 3 onions. We have the following system of equations:

$\begin{cases}a+b=7,\\8a+3b=41\end{cases}$

Subtracting $b$ from both sides of the first equation, we get $a=7-b$ . Substitute this into the second equation:

$8(7-b)+3b=41,\\56-8b+3b=41,\\56-5b=41,\\-5b=-15,\\b=\boxed{3}$

Therefore, the number of 8-onion bags is:

$a=7-b,\\a=7-3,\\a=\boxed{4}$

Thus, the chef got 4 8-onion bags and 3 3-onion bags.

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3 years ago

How do you Use Trigonometry to find length

Ivan

Right Triangles and the Pythagorean Theorem

The Pythagorean Theorem, a2+b2=c2, a 2 + b 2 = c 2 , can be used to find the length of any side of a right triangle.

The side opposite the right angle is called the hypotenuse (side c in the figure).

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3 years ago

Show that the equation x^3+6x-5=0 has a solution between x=0 and x=1

Mnenie [13.5K]

Answer:

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

Step-by-step explanation:

The equation f(x) given is:

$f(x) = x^3+6x-5$

For x = 0. the value of the expression is:

$f(0) = 0^3+0-5\\f(0) = -5$

For x = 1, the value of the expression is:

$f(1) = 1^3+6-5\\f(1)=2$

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

In other words, there is at least one solution for the equation between x=0 and x=1.

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3 years ago

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