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3 years ago

1 1/16 cups of butter times 20 equals how much

Mathematics

2 answers:

iren2701 [21]3 years ago

8 0

13.75 Cups in us cups

Maksim231197 [3]3 years ago

3 0

Answer:

13.75

Step-by-step explanation:

If you turn 11/16 into a decimal by doing 11 divided by 16 which would be 0.6875. Once you have that you can multiply 0.68 by 20 and get 13.75

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Convert: 35 pounds, 24 ounces=_ ounces

LenaWriter [7]

Answer:

Step-by-step explanation:

1 pound = 16 ounces

35 pounds = 560 ounces + 24 ounce = 584ounces

8 0

3 years ago

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F(x) = -12x + 5. Find f(-3).

JulijaS [17]

Answer:

f(-3) = 41

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

f(x) = -12x + 5

f(-3) is x = -3

Step 2: Evaluate

Substitute in x: f(-3) = -12(-3) + 5
Multiply: f(-3) = 36 + 5
Add: f(-3) = 41

5 0

3 years ago

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Whole number less then 15

Alexeev081 [22]

Answer:

Step-by-step explanation:

your options are 1 2 3 4 5 6 7 8 9 10 11 12 13 or 14

6 0

3 years ago

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You are in charge of erecting a radio telescope on a newly discovered planet. To minimize interference, you want to place it whe

strojnjashka [21]

Answer:

Step-by-step explanation:

$\text{The equation of the surface of the sphere whose radius is 6 can be represented as:}$

$x^2+y^2+z^2 = 36}$

$So , g(x,y,z) = x^2 + y^2 + z^2 - 36$

$\text{To minimize the function :} \\ \\ M(x,y,z0 = 6x - y^2 +xz + 60$

$\text{by applying lagrange multipliers }$

$\bigtriangledown M (x,y,z) = \lambda \bigtriangledown g(x,y,z)$

$\langle 6+zz,-2y,x \rangle = \lambda \langle 2x,2y,2z \rangle$

$6+z = 2\lambda x$

$-2y = 2 \lambda y$

$\text{from the second equation ;} (\lambda +1)y = 0, \text{so , it is either y =0 or }\lambda = -1$

$Suppose \ \lambda = -1 ; \text{other equation becomes x = -2z and 6+z = -2x}$

$\text{such that; 6+z =4z or z = 2}$

$\text{it implies that: x= -4 and }y = \pm \sqrt{36 - 4-16} = \pm 4$

$\text{Here; there exist two possible points}$

$\text{(-4,-4,2) and (-4,4,2)}$

$\text{In the scenario here y=0,} \lambda \text{ is unknown, then we remove it}$

$x = 2 \lambda z \\ \\ 6+z = 2 \lambda x \\ \\ 6+z = 4 \lambda ^2z \\ \\ 6 = (4 \lambda ^2 -1) z ---(1)$

$z = \dfrac{6}{4 \lambda ^2 -1}$

$x = \dfrac{12 \lambda }{4 \lambda ^2 -1 }$

$\text{recall that; it i possible to divide }4 \lambda ^2 -1 \text{since (1) shows that it cannot be equal to zero.} \\ \\ \text{hence, puttinf this into constraint, whereby y =0, Then:}$

$144 \lambda ^2 + 36 = 36(4\lambda ^2 -1) \\ \\ 4\lambda ^2 ( 4\lambda ^2-3) =0 \\ \\ \lambda = 0 \ or \ \lambda = \pm \dfrac{\sqrt{3}}{2}$

$\text{Thus; the points are:} \\ \\ (0,0,6) \ and \ (\pm 3\sqrt{3},0,3})$

$Now;$

$M(-4,-42) = 12 \\ \\ M(-4,4,2) = 28 \\ \\ M(0,0,6) = 60 \\ \\ M(3\sqrt{3},0,3) = 27\sqrt{3} + 60 \\ \\ M(-3\sqrt{3},0,3) = -27\sqrt{3} +60$

$\text{Hence, the minimum is 12 which occurs at (-4,-4,2)}$

4 0

3 years ago

Is the quotient 2/3 • 3/8 grater or less than 1

satela [25.4K]

the answer is less than because when you multiple 2/3 by 3/8 you get 6/24 but then you simplify and you get 1/4 which is less than 1

4 0

3 years ago