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3 years ago

5x-3y=21 Solve for Y

1 answer:

7 0

You first subtract 5x from both sides and end up with -3y=21-5x. In order to isolate the variable you need to divide -3 from both sides. Your equation would then be y= -7+ 5/3x. I hope this helps love! :)

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How many cups of ketchup would 13 hamburgers get if there was 3 1/4 cups of ketchup to be equally split among the 13 burgers? (i

Setler [38]

.25 cups of ketchup for each hamburger

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2 years ago

The ideal (daytime) noise-level for hospitals is 45 decibels with a standard deviation of 10 db; which is to say, this may not b

WINSTONCH [101]

Answer:

(a) A 99% confidence interval for the actual mean noise level in hospitals is (44.02 db, 49.98 db).

(b) We can be 90% confident that the actual mean noise level in hospitals is 47 db with a margin of error of 1.89 db.

(c) Unless our sample (of 81 hospitals) is among the most unusual 2% of samples, the actual mean noise level in hospitals is between 44.41 db and 49.59 db.

Step-by-step explanation:

The problem is incomplete. The questions are:

(a) A 99% confidence interval for the actual mean noise level in hospitals is (44.02 db, 49.98 db).

For a 99% CI, the value of z is z=2.58

Then, the confidence interval for the mean is:

$M-z\sigma/\sqrt{n}\leq\mu\leq M-z\sigma/\sqrt{n}\\\\47-2.58*10/\sqrt{75} \leq\mu\leq47+2.58*10/\sqrt{75}\\\\47-2.98\leq\mu\leq47+2.98\\\\44.02\leq\mu\leq 49.98$

(b) We can be 90% confident that the actual mean noise level in hospitals is 47 db with a margin of error of 1.89 db.

For a 90% CI, the value of z is z=1.64.

Then, we can calculate the margin of error as:

$E=z*\sigma/\sqrt{n}=1.64*10/\sqrt{75}=1.89$

(c) Unless our sample (of 81 hospitals) is among the most unusual 2% of samples, the actual mean noise level in hospitals is between 44.41 db and 49.59 db.

The 2% tails data corresponds, in the standard normal distirbution, to the values of z whose absolute value is higher than 2.33.

The values of db for these critical values are:

$X_1=M+z_1*\sigma/\sqrt{n}=47+(-2.33)*10/\sqrt{81}=47-2.59=44.41\\\\\\ X_2=M+z_2*\sigma/\sqrt{n}=47+(2.33)*10/\sqrt{81}=47+2.59=49.59$

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3 years ago

Peter takes 7 minutes and 30 seconds to run 1 mile. How many miles can he run in 15 minutes?

goblinko [34]

2 miles in 15 mins.. i think.

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3 years ago

Read 2 more answers

Find the GCF 4x^5y^3+8x^4y^4+4x^3y^2

Alekssandra [29.7K]

$4x^5y^3+8x^4y^4+4x^3y^2$

GCF is the greatest common factor

We take GCF of numbers first and then we take GCF for variables

GCF of 4, 8, 4 is 4 because all the numbers are divisible by 4

For variable, lowest exponent is our GCF

GCF of $x^5+x^4+x^3$ is x^3

GCF of $y^3+y^4+y^2$ is y^2

So GCF is 4x^3y^2

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2 years ago

Order these numbers from least to greatest. 2.103, 2.1, 2.13, 2.1312

LiRa [457]

Answer:

2.1 , 2.103 , 2.13 , 2.1312

Step-by-step explanation:

Look at the first place, and see if it's the same, if it is, then you move to the next place. If the place is empty, fill it with a 0 and go from there.

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3 years ago