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3 years ago

5x-3y=21 Solve for Y

1 answer:

7 0

You first subtract 5x from both sides and end up with -3y=21-5x. In order to isolate the variable you need to divide -3 from both sides. Your equation would then be y= -7+ 5/3x. I hope this helps love! :)

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Help help help please

OverLord2011 [107]

Answer:

-5-2i

Step-by-step explanation:

Its already simplified

8 0

3 years ago

Pre-Calc help:

stepladder [879]

Answer:

$8x^2+8y^2-79x-32y+95=0$

Step-by-step explanation:

Let the equation be : $x^2+y^2+2gx+2fy+c=0$

The point (1,1) must satisfy this equation.

$1^2+1^2+2g*1+2f*1+c=0\\2g+2f+c=-2---(1)$

Similarly, the point (1,3) must satisfy:

$1^2+3^2+2g*1+2f*3+c=0\\1+9+2g+6f+c=0\\2g+6f+c=-10---(2)$

Also for the point (9,2), we have:

$9^2+2^2+2g*9+2f*2+c=0\\81+4+18g+4f+c=0\\18g+4f+c=-85---(3)$

Solving the equations (1), (2) and (3) simultaneously, we get:

$g=-\frac{-79}{16},f=-2,c=\frac{95}{8}$

We Substitute this values to get:

$x^2+y^2+2(\frac{-79}{16})x+2(-2)y+\frac{95}{8}=0$

$x^2+y^2-(\frac{79}{8})x-4y+\frac{95}{8}=0$

Multiply through by 8 to get:

$8x^2+8y^2-79x-32y+95=0$

8 0

3 years ago

What is 8x6+2x7=350 ?

GaryK [48]

use pemdas

8 * 6 + 2 * 7 =

48 + 14 =

6 0

3 years ago

Read 2 more answers

Need help ASAP Will mark as Brainiest

Kisachek [45]

Step-by-step explanation:

x²-11x+32=4

x²-11x+28=0

(x-4)(x-7)=0

x=4 or x=7

_______

x²+8x-5=4

x²+8x-9=0

(x+9)(x-1)=0

x=-9 or x=1

_______

x²+x+4=5x+1

x²-4x+3=0

(x-1)(x-3)=0

x=1 or x=3

________

x²+x-24=-8x-2

x²+9x-22=0

(x+11)(x-2)=0

x=-11 or x=2

7 0

3 years ago

Temperature in degrees Fahrenheit is equal to 32 more than 9/5 times the temperature in degrees Celsius . One day the high tempe

bazaltina [42]

The high temperature is 35 degree celsius

Solution:

Given that, Temperature in degrees Fahrenheit is equal to 32 more than 9/5 times the temperature in degrees Celsius

Let "f" be the temperature in degree Fahrenheit

Let "c" be the temperature in degree celsius

Therefore,

Temperature in degrees Fahrenheit = 32 + $\frac{9}{5}$ times the temperature in degrees Celsius

$f = 32 + \frac{9}{5} \times c$

One day the high temperature in Edison. Nj was 95 degrees Fahrenheit

f = 95 ; c = ?

Substitute f = 95 in above equation

$95 = 32 + \frac{9c}{5}\\\\95=\frac{32 \times 5 +9c}{5}\\\\95 \times 5 = 160+9c\\\\475 = 160 + 9c\\\\9c = 475 - 160\\\\9c = 315\\\\c = 35$

Thus high temperature in degrees Celsius is 35 degree celsius

5 0

3 years ago