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Assoli18 [71]
4 years ago
12

Find the product using FOIL. (3z+3)(5z+8)

Mathematics
2 answers:
Verdich [7]4 years ago
8 0

Answer:

15z² + 39z + 24

Step-by-step explanation:

(3z+3)(5z+8)

(3z×5z) + (3z×8) + (3×5z) + (3×8)

15z² + 24z + 15z + 24

15z² + 39z + 24

attashe74 [19]4 years ago
7 0

Using FOIL you multiply each term in the first set of parentheses by each term in the other set, then combine all like terms:

(3z+3)(5z+8)

3z x 5z = 15z^2

3z x 8 = 24z

3 x 5z = 15z

3 x 8 = 24

So you now have:

15z^2 + 24z + 15z + 24

Simplify to:

15^2 + 39z + 24

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What is 2/5 divided by -1/2 minus 3/2
shutvik [7]

Answer:

-  \frac{23}{10}

Step-by-step explanation:

\frac{2}{5}  \div  \frac{ - 1}{2}  -  \frac{3}{2}

➡️ -  \frac{2}{5}  \times 2 -  \frac{3}{2}

➡️ -  \frac{4}{5}  -  \frac{3}{2}

➡️ -  \frac{23}{10}

5 0
3 years ago
Read 2 more answers
What is the value of x...<br><br> 5(x-5)=3(x-7)
timurjin [86]

Answer:

x=2

Step-by-step explanation:

5(x-5)=3(x-7)

Distribute

5x-25 = 3x-21

subtract 3x from each side

5x-25-3x = 3x-21-3x

2x-25 = -21

Add 25 to each side

2x-25+25 = -21 +25

2x=4

Divide by 2

2x/2 =4/2

x=2

8 0
3 years ago
Find the area of the red shaded region round to the nearest tenth.
sattari [20]

Answer:

28.5 in²

Step-by-step explanation:

find the area of the quarter circle:

(pi x r²)/4

100pi/4 =

25pi

To get the shaded region minus the triangle from the quarter circle:

Formula for triangle is bh/2

25 pi - Area of triangle

25 pi - (10x10)/2

25pi - 50

Which is approximately 28.5 square inches.

4 0
2 years ago
$49.95 CD player; 5% discount
velikii [3]
Because there is no actual question, I'll just tell you relevant information, the discount is worth approximately $2.50 and the price of the CD player is 47.45
5 0
3 years ago
Write as an improper fraction-3 3/11
FinnZ [79.3K]

Answer: The answer is -36/11

Step-by-step explanation:

Multiply the denominator by the whole number to get 33.

Then, add 33 to the numerator to get 36 and that's your answer.    Hope this helps!

8 0
3 years ago
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