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Sever21 [200]
4 years ago
7

What is the highest of 120 and 150

Mathematics
2 answers:
Soloha48 [4]4 years ago
5 0
Answer:  150 is the highest value.

Given the following two values:  "120" and "150" ;  "150" is the highest value.
_____________________________________________
AleksAgata [21]4 years ago
3 0
150 if you mean which of the two is the highest. Not sure how this is 'high school math'
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The cost of five books is $36.25. What is the unit price?​
zimovet [89]

Step-by-step explanation:

Cost of 5 books = $ 36.25

Cost of 1 book = $36.25 / 5 = $ 7.25

The unit price is $ 7.25

Hope it will help :)

7 0
3 years ago
Julius drank 1.36 liters
tino4ka555 [31]

Answer:

1.4 liters of water

Step-by-step explanation:

the thenth place is the first number behind the decimal. then if the second number the decimal is higher than 5 you round up and in this case you round up because its over 5. - Hopes this helps !!

5 0
3 years ago
Can someone pls help will mark u as brainliest
Gnom [1K]

Answer:

9*((2-1)/9)

or

<u>2</u><u> </u><u>-</u>1

9

<u>2-9</u><u> </u>=<u>-7</u>

9. 9

9× <u>-7</u>

9

=<u>-7</u>

<u>2-</u> <u>3</u>

9. -3

=(1.22222222222)

or

11/9

or

1*(2/9)

5 0
3 years ago
A fast-food restaurant has an automated beverage machine that dispenses a set amount of liquid based on a size setting. Suppose
SashulF [63]

Answer:

n=(\frac{2.58(17)}{10})^2 =19.24 \approx 20

So the answer for this case would be n=20 rounded up to the nearest integer would be the sample required to obatin a margin of erros or 10 ml at 99% of confidence

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma =17 represent the population standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =10 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.005;0;1)", and we got z_{\alpha/2}=2.58, replacing into formula (b) we got:

n=(\frac{2.58(17)}{10})^2 =19.24 \approx 20

So the answer for this case would be n=20 rounded up to the nearest integer would be the sample required to obatin a margin of erros or 10 ml at 99% of confidence

8 0
3 years ago
Determine whether the three points are collinear. (3, -10), (-2, -7), (0, -5)
Mumz [18]

The points are not collinear.

Solution:

Let A, B and C be (3, -10), (-2, -7) and (0, -5).

<em>If slopes of any two points are same, then the points are collinear.</em>

Slope formula:

$m=\frac{y_2-y1}{x_2-x_1}

<u>Slope of AB:</u>

$m_1=\frac{-7-(-10)}{-2-3}

$m_1=\frac{-7+10}{-5}

$m_1=-\frac{3}{5}

<u>Slope of BC:</u>

$m_2=\frac{-5-(-7)}{0-(-2)}

$m_2=\frac{-5+7}{2}

$m_2=\frac{2}{2}

m_2=1

<u>Slope of CA:</u>

$m_3=\frac{-10-(-5)}{3-0}

$m_3=\frac{-10+5}{3}

$m_3=-\frac{5}{3}

m_1\neq m_2 \neq m_3

Slope of AB ≠ Slope of BC ≠ Slope of AC

Therefore the points are not collinear.

6 0
3 years ago
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