Answer:
5
Step-by-step explanation:
Plug n the h and j so you get 6-(2-1). Due to PEMDAS you do the parenthesis first then subtract so it become 6-1=5. ( You could use distributive property)
<span>You are to find the maximum amount of baggage that may be loaded aboard the airplane for the cg (center of gravity) to remain within the moment envelope.
In order to solve this, there is a graph that shows the load weight and the load moment of pilot and front passenger, fuel, rear passenger and passenger including the baggage. Using the given data such as pilot and front passenger 250, the load moment is 9 lbs/in, for the rear passenger at 400lbs, the load moment is 28.5 lbs/in, the fuel at 30 gal has a load moment of 2 lbs/in and oil at 8 quarters is 15 lbs. The total weight is 1,350 + 250 + 400 + 15 is 2015 lbs.</span>
Answer:
20°
Step-by-step explanation:
One way of doing this is to find the constant of proportionality, k:
8k + 6k + 4k = 90° Then 18k = 90°, and k turns out to be 90/18, or 5.
Then the angles are 8(5), 6(5) and 4(5). The smallest of these angles is thus 20°
4 because you have 6 equal groups . 6 x ? = 24 answer 4
Answer:
80x3 - 180x2 + 109x - 20
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4
Step-by-step explanation:
