Hurry please <br><br> Express $112 for 14 hours as a unit rate

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Pie

For this case we have by definition, that the equation of a line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cutoff point with the y axis

We need two points through which the line passes to find the slope:

$(0, -4)\\(1,0)$

We found the slope:

$m = \frac {y2-y1} {x2-x1}\\m = \frac {0 - (- 4)} {1-0} = \frac {4} {1} = 4$

So, the equation is of the form:

$y = 4x + b$

We substitute a point to find "b":

$-4 = 4 (0) + b\\-4 = b$

Finally, the equation is:

$y = 4x-4$

Answer:

Option D

4 0

2 years ago

Here’s a graph of a linear function. Write the equation that describes that function. Express it in slope intercept form.

MatroZZZ [7]

Answer:

y = $\frac{3}{4\\}$ x + 2

Step-by-step explanation:

To find the slope:

Find two spots where the line intersects and exact point. (-8,-4)(-4,-1)

Either count up & over or do y1-y2 / x1-x2 (-4+1)/(-8+4) -3/-4 3/4

The intercept is where it crosses the y-axis, in this case 2

Write the equation like this y = mx + b where m=slope & b=intercept

y = 3/4x + 2

4 0

3 years ago

Find the value of the probability of the standard normal variable Z corresponding to this area for problems 1-3.

Semenov [28]

Answer:

Explained below.

Step-by-step explanation:

The complete question is:

Find the value of the probability of the standard normal variable Z corresponding to this area for problems 1-3.

1. P(Z < 1.62)

2. P(Z > -1.57)

3. P(-1.41 < Z < 0.63)

Solution:

Use Excel to solve the problems.

(1)

P(Z < 1.62) =NORM.S.DIST(1.62,TRUE)

= 0.9474

(2)

P(Z > -1.57) = P (Z < 1.57)

=NORM.S.DIST(1.57,TRUE)

= 0.9418

(3)

P(-1.41 < Z < 0.63) = P (Z < 0.63) - P (Z < -1.41)

=NORM.S.DIST(0.63,TRUE) - NORM.S.DIST(-1.41,TRUE)

= 0.7357 - 0.0793

= 0.6564

7 0

2 years ago

Find missing measure

Genrish500 [490]

Answer:

Step-by-step explanation:

∠Q = 180-∠T = 89°

∠S = 360-∠T-∠Q-∠R = 360-91-89-27 = 153°

8 0

2 years ago

A pebble is dropped into a deep well and 3s later the sound of a splash is heard as the pebble reaches the bottom of the well. T

ankoles [38]

Answer:

$2.89\ \text{s}$

0.11 seconds

$37.4\ \text{m}$

Step-by-step explanation:

$t_1$ = Time taken by the pebble to hit the water

$t_2$ = Time taken by the sound to travel to the observer

$t_1+t_2$ = Time taken by the observer to listen to the splash after stone is thrown = 3 s

$t_1=3-t_2$

a = g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

$u_s$ = Speed of sound = 340 m/s

The distance traveled by the pebble

$s=ut+\dfrac{1}{2}at_1^2\\\Rightarrow s=0+\dfrac{1}{2}\times9.81(3-t_2)^2\\\Rightarrow s=4.905(9+t_2^2-6t_2^2)$

Distance traveled by the sound

$s=u_st\\\Rightarrow s=340\times t_2$

The distance traveled by the sound and the pebble is equal

$4.905(9+t_2^2-6t_2)=340\times t_2\\\Rightarrow 9+t_2^2-6t_2=\dfrac{340}{4.905}t_2\\\Rightarrow 9+t_2^2-6t_2=69.32t_2\\\Rightarrow t_2^2-75.32t_2+9=0\\\Rightarrow t_2=\frac{-\left(-75.32\right)\pm \sqrt{\left(-75.32\right)^2-4\times \:1\times \:9}}{2\times \:1}\\\Rightarrow t_2=75.2,0.11$

Since $t_1+t_2=3$ the value of $t_2$ cannot be greater than 3.

So, time taken by the sound to reach the observer is 0.11 seconds.

Time taken by the pebble to hit the water is $t_1=3-t_2=3-0.11=2.89\ \text{s}$

Depth of the well is $s=340t_2=340\times 0.11=37.4\ \text{m}$

8 0

2 years ago

Hurry please Express $112 for 14 hours as a unit rate