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3 years ago

Simplify: 3 5/8+2 11/2+4 3/4

Mathematics

1 answer:

gladu [14]3 years ago

5 0

Answer:

15 7/8

Step-by-step explanation:

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Stuck on this test answer all four

NARA [144]

Answer:

8.) u=12.37

16.) p=75

17.) m=52

18.) n=112

Step-by-step explanation:

u-2.07=10.3

u=12.37

5=p/15

p=75

m/26=2

m=52

n/16=7

n=112

6 0

3 years ago

find a curve that passes through the point (1,-2 ) and has an arc length on the interval 2 6 given by 1 144 x^-6

taurus [48]

Answer:

$f(x) = \frac{6}{x^2} -8$ or $f(x) = -\frac{6}{x^2} + 4$

Step-by-step explanation:

Given

$(x,y) = (1,-2)$ --- Point

$\int\limits^6_2 {(1 + 144x^{-6})} \, dx$

The arc length of a function on interval [a,b]: $\int\limits^b_a {(1 + f'(x^2))} \, dx$

By comparison:

$f'(x)^2 = 144x^{-6}$

$f'(x)^2 = \frac{144}{x^6}$

Take square root of both sides

$f'(x) =\± \sqrt{\frac{144}{x^6}}$

$f'(x) = \±\frac{12}{x^3}$

Split:

$f'(x) = \frac{12}{x^3}$ or $f'(x) = -\frac{12}{x^3}$

To solve fo f(x), we make use of:

$f(x) = \int {f'(x) } \, dx$

For: $f'(x) = \frac{12}{x^3}$

$f(x) = \int {\frac{12}{x^3} } \, dx$

Integrate:

$f(x) = \frac{12}{2x^2} + c$

$f(x) = \frac{6}{x^2} + c$

We understand that it passes through $(x,y) = (1,-2)$ .

So, we have:

$-2 = \frac{6}{1^2} + c$

$-2 = \frac{6}{1} + c$

$-2 = 6 + c$

Make c the subject

$c = -2-6$

$c = -8$

$f(x) = \frac{6}{x^2} + c$ becomes

$f(x) = \frac{6}{x^2} -8$

For: $f'(x) = -\frac{12}{x^3}$

$f(x) = \int {-\frac{12}{x^3} } \, dx$

Integrate:

$f(x) = -\frac{12}{2x^2} + c$

$f(x) = -\frac{6}{x^2} + c$

We understand that it passes through $(x,y) = (1,-2)$ .

So, we have:

$-2 = -\frac{6}{1^2} + c$

$-2 = -\frac{6}{1} + c$

$-2 = -6 + c$

Make c the subject

$c = -2+6$

$c = 4$

$f(x) = -\frac{6}{x^2} + c$ becomes

$f(x) = -\frac{6}{x^2} + 4$

3 0

3 years ago

What is y if x = 4 for the function y = 3x + 9?

Evgen [1.6K]

Value of y

<h3>Given:-</h3>

x= 4

<h3>Solution :-</h3>

⟹ y = 3x + 9

⟹ y = 3 × 4 + 9

⟹ y = 12 + 9

4 0

3 years ago

PLEASE HELP ME!!! I’m struggling on math (proportional relationships) and I need help (on both questions) there are 2 options to

ira [324]

Answer:

Bennet is wrong. Betty is also right.

Step-by-step explanation:

More than 7 minutes that would be 350 rotations and over

6 0

4 years ago

Find the constant of variation k in the case that y varies inversely as the square of x, and y=6 when x=3.

Len [333]

K=54.....y=k/x²....6=k/9.....k=9*6....=54

6 0

4 years ago