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REY [17]
3 years ago
13

Stuck on this test answer all four

Mathematics
1 answer:
NARA [144]3 years ago
6 0

Answer:

8.) u=12.37

16.) p=75

17.) m=52

18.) n=112

Step-by-step explanation:

u-2.07=10.3

u=12.37

5=p/15

p=75

m/26=2

m=52

n/16=7

n=112

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3 years ago
Does anyone how to solve this sum? It’s urgent
Galina-37 [17]

The required value for the sum is 9580.


\frac{10000}{(1+\frac{0.115}{4})^2}+68\frac{1-\frac{1}{(1+\frac{0.115}{4})^2}}{\frac{0.115}{4}}

<h3>What is simplification?</h3>

Simplification in mathematics to solve the given condition on its operators.


\frac{10000}{(1+\frac{0.115}{4})^2}+68\frac{1-\frac{1}{(1+\frac{0.115}{4})^2}}{\frac{0.115}{4}}

= \frac{10000}{1.028^2} +68*\frac{1-\frac{1}{1.028^2} }{\frac{0.115}{4} } \\9451+68*\frac{1-0.94}{\frac{0.115}{4} } \\\\9451+68*\frac{0.054}{\frac{0.115}{4} } \\\\\\9451+3.72{\frac{4}{0.115} } \\\\\\9451+129\\

= 9580


The required solution is given as 9580.

Learn more about simplification here:
brainly.com/question/9218183

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4 0
2 years ago
A sign company charges $28 per yard for each custom made banner. Ms. Gill orders two banners that are each 1 7/8 yards yards lon
Svetlanka [38]

Answer:

$896

Step-by-step explanation:

We are given that

Charge of 1 yard for each custom-made banner=$28

Length of 1 piece=15 yards

Length of another piece=2 yards

We have to find that how much money payed by Ms.Gill for all three banners.

According to question

Cost of 15 yards long banner=$420

Cost of 2 piece of 15 yards long banner==$840

Cost of 2 yards long banner==$56

Total cost of 3 piece of banners=840+56=$896

Hence, Ms gill pay for all three banners=$896

Your Welcome;)

8 0
3 years ago
12-8÷2=8 but, (12-8)÷2=2<br><br>​
Aneli [31]

Answer:

hope it helps you to understand

6 0
3 years ago
Read 2 more answers
PLEASE HELP DUE TOMORROW 1. An artist is selling children’s crafts. Necklaces cost 2.25 each and bracelets cost 1.50 per each. a
Tems11 [23]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that:

Cost per bracelet = 1.50

Cost per necklace = 2.25

Let :

number of necklace = n

Number of bracelet = b

Cost equation C ;

C = 1.5b + 2.25n

Number of necklace that could be sold for exactly $12

5 necklaces and 1 bracelet :

1.5 + 2.25(5) = 12.75

•2 necklaces and 5 bracelets:

1.5(5) + 2.25(2) = 12

• 3 necklaces and 3 bracelets

1.5(3) + 2.25(3) = 11.25

• 4 necklaces and 2 bracelets

1.5(2) + 2.25(4) = 12

• 3 necklaces and 5 bracelets

1.5(5) + 2.25(3) = 14.25

• 6 necklaces and no bracelets •

1.5(0) + 2.25(6) = 13.5

No necklaces and 8 bracelets

1.5(8) + 2.25(0) = 12

Amount charged per Tshirt = c

Setup fee = $40

Number of students in drama club = 21

Total cost of order = $187

Calculate C ;

Total order cost = set up fee + (cost per shirt * number of shirts)

Total order cost = 40 + 21c

187 = 40 + 21c

187 - 40 = 21c

147 = 21c

c = 147 / 21

C = 7

Hence cost per shirt = $7

5 0
3 years ago
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