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Mila [183]
3 years ago
8

What is the sum of the geometric sequence 4, 16, 64, ... if there are 8 terms? (6 points)

Mathematics
1 answer:
PtichkaEL [24]3 years ago
6 0

Answer:

87380

Step-by-step explanation:

The sum to n terms of a geometric sequence is

S_{n} = \frac{a(r^n-1)}{r-1}

where a is the first term and r the common ratio

r = \frac{16}{4} = 4 and a = 4, hence

S_{8} = \frac{4(4^8-1)}{4-1} = \frac{4(65535)}{4} = 87380

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