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Fudgin [204]
3 years ago
7

(Fill in the blank) ____ two points are collinear. A. Any B. No C. Sometimes

Mathematics
1 answer:
Zigmanuir [339]3 years ago
4 0

Any two points are collinear.

<h3>Further explanation</h3>
  • All points in a straight line are called collinear. The two points are always collinear because we can continue to connect them in a straight line.
  • Therefore, at least two points can form a line and are considered collinear.
  • All points can, also, be said to be coplanar. This is because in addition to these points forming a line they must also lie on a planar surface.
  • Noncollinear points are the points that do not lie in a similar straight line.

Let us practice other alternative questions.

(Fill in the blank) ____ three points are collinear.

A. Any

B. No

C. Sometimes

The answer:

Sometimes three points are collinear.

Three points may be collinear or not. We can consider a triangle consisting of three points that are not collinear. All triangle vertices are called coplanar.

<h3>Learn more</h3>
  1. Which points are coplanar and noncollinear? brainly.com/question/4165000
  2. What are the names of three collinear points? brainly.com/question/5191341
  3. Comparing collinear points and coplanar points. brainly.com/question/1593959
  4. Which defines a Line segment?  brainly.com/question/909890

Keywords: fill in the blank, any two points are collinear, no, sometimes, connect them, straight line, at least, a planar surface, three points, not, a triangle, vertices, coplanar,

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Answer:

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2. y = -1; (0, -1)

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4. y = 0; (8/7, 0)

5. y = 3/4; (2, 3/4)

Step-by-step explanation:

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A right cylinder has a diameter of 10 in and height of 15 in. Find the surface area of the cylinder.
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628.32 in.²

Step-by-step explanation:

Height: 15 in.

Diameter: 10 in.

Radius: 5 in.

A = 2πrh + 2πr²

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Answer:

  • A -- base 3, height 4
  • B -- base 4, height 4
  • C -- base 3, height 3
  • D -- base 3, height 5

Step-by-step explanation:

A sort of straightforward way to approach this is to define base and height variables for each of the figures: ba, ha, bb, hb, bc, hc, bd, hd. Then the statements can be used to make equations in these variables.

0. hc = bc . . . . figure C is a square

1. ba = bd

2. ba = bb -1

3. hc = ba

4. hb = ha = bb

5. hc·bc = 9

6. (1/2)ha·ba +(1/2)hb·bb +hc·bc+hd·bd = 38

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Using equations 0 and 5, we find ...

  hc² = 9   ⇒   hc = 3

From equation 3, ...

  ba = 3

From equation 2, ...

  3 = bb -1   ⇒   bb = 4

From equation 1, ...

  bd = 3

From equation 4, ...

  ha = hb = 4

Filling in the values we know in equation 6, we get ...

  (1/2)(4)(3) +(1/2)(4)(4) +9 +hd(3) = 38

  23 +3hd = 38

  hd = 15/3 = 5

The dimensions are:

  • A -- base 3, height 4
  • B -- base 4, height 4
  • C -- base 3, height 3
  • D -- base 3, height 5
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