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3 years ago

Here is a picture of a math problem

Mathematics

1 answer:

tresset_1 [31]3 years ago

3 0

Answer:

Step-by-step explanation:

Area = Base × Height

$10 = 2 \frac{1}{7} \times h \\\\ 2 \frac{1}{7} = \frac{7}{7} + \frac{7}{7} + \frac{1}{7} = \frac{15}{7} \\\\ 10 = \frac{10}{1} = \frac{70}{7} \\\\h \times \frac{15}{7} = \frac{70}{7} \\\\ h = \frac{\frac{70}{7}}{\frac{15}{7}} \\\\\ h = \frac{70}{7} \times \frac{7}{15} \\\\ h = \frac{70}{15} \\\\ h = \frac{14}{3} \\\ h = 4 \frac{2}{3}$

I hope I helped you.

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What is the perimeter of the figure

anastassius [24]

Answer:

Option A.

$P=73.4\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

In this problem we have a triangle with a circle inscribed in it

$A.F=A.B\\C.B=C.D\\E.F=E.D$

step 1

Find the length side B.C

$C.B=A.C-A.B$

substitute the given values

$C.B=23-14=9\ units$

step 2

Find the length side C.D

Remember that

$C.D=C.B$

therefore

$C.D=9\ units$

step 3

Find the length side E.D

we know that

$E.D=E.C-C.D$

substitute the given values

$E.D=22.7-9=13.7\ units$

step 4

Find the length side E.F

Remember that

$E.F=E.D$

therefore

$E.F=13.7\ units$

step 5

Find the length side A.F

Remember that

$A.F=A.B$

therefore

$A.F=14\ units$

step 6

Find the perimeter

$P=23+22.7+13.7+14$

$P=73.4\ units$

6 0

3 years ago

Convert 1 = 4 to polar form.

dimaraw [331]

Answer:The inverse tangent of 14 is θ=14.03624346° θ = 14.03624346 ° . This is the result of the conversion to polar coordinates in (r,θ) form.

Step-by-step explanation: i think this may help you

3 0

3 years ago

Fill in the blanks people!

MakcuM [25]

I can’t understand what you are asking for

8 0

3 years ago

3x - 4y = -16<br> 2x - 4y = -8<br> what is x and y

FinnZ [79.3K]

Answer:

x = -8 , y = -2

Step-by-step explanation:

Solve the following system:

{3 x - 4 y = -16 | (equation 1)

2 x - 4 y = -8 | (equation 2)

Subtract 2/3 × (equation 1) from equation 2:

{3 x - 4 y = -16 | (equation 1)

0 x - (4 y)/3 = 8/3 | (equation 2)

Multiply equation 2 by 3/4:

{3 x - 4 y = -16 | (equation 1)

0 x - y = 2 | (equation 2)

Multiply equation 2 by -1:

{3 x - 4 y = -16 | (equation 1)

0 x+y = -2 | (equation 2)

Add 4 × (equation 2) to equation 1:

{3 x+0 y = -24 | (equation 1)

0 x+y = -2 | (equation 2)

Divide equation 1 by 3:

{x+0 y = -8 | (equation 1)

0 x+y = -2 | (equation 2)

Collect results:

Answer: {x = -8 , y = -2

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3 years ago

Find the minimum and maximum of f(x, y, z) = y + 4z subject to two constraints, 2x + z = 4 and x2 + y2 = 1. g

yuradex [85]

$L(x,y,z,\lambda_1,\lambda_2)=y+4z+\lambda_1(2x+z-4)+\lambda_2(x^2+y^2-1)$

$L_x=2\lambda_1+2\lambda_2 x=0\implies\lambda_1+\lambda_2x=0$
$L_y=1+2\lambda_2y=0$
$L_z=4+\lambda_1=0\implies\lambda_1=-4$
$L_{\lambda_1}=2x+z-4=0$
$L_{\lambda_2}=x^2+y^2-1=0$

$\lambda_1=-4\implies \lambda_2x=4\implies\lambda_2=\dfrac4x$
$1+2\lambda_2y=0\implies\lambda_2y=-\dfrac12\implies8y=-x$

$x^2+y^2=1\implies (-8y)^2+y^2=65y^2=1\implies y=\pm\dfrac1{\sqrt{65}}$
$y=\pm\dfrac1{\sqrt{65}}\implies x=\mp\dfrac8{\sqrt{65}}$
$2x+z=4\implies z=4\pm\dfrac{16}{\sqrt{65}}$

We have two critical points to consider: $\left(-\dfrac8{\sqrt{65}},\dfrac1{\sqrt{65}},4+\dfrac{16}{\sqrt{65}}\right)$ and $\left(\dfrac8{\sqrt{65}},-\dfrac1{\sqrt{65}},4-\dfrac{16}{\sqrt{65}}\right)$ .

At these points, we respectively have a maximum of $16+\sqrt{65}$ and a minimum of $16-\sqrt{65}$ .

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3 years ago