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3 years ago

(Please answer fast)

Mathematics

1 answer:

Paladinen [302]3 years ago

6 0

we will first calculate the cost of each month, then for each day and then for each period and then for each minute.

cost per month = 10750/10 = 1075

considering each month has 30 days

cost for each day = 1075/30 =

cost for each period = 1075/(30×7)

cost for each minute = 1075/(30×7×45)

=$ 0.11375

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BRAINLIEST ANSWER WINS! A satellite is to be put into an elliptical orbit around a moon as shown below. A vertical ellipse is sh

bekas [8.4K]

Answer:

D. x²/1953² + y²/ 1466² = 1

Step-by-step explanation:

==>Given:

Radius of spherical moon = 1000km

Distance of satellite from moon surface = 953km to 466km

==>Required:

Derived equation of ellipse

==>Solution:

The formula for driving an equation of ellipse is given as:

x²/a² + y²/b² = 1

Where,

a = length of the semi-major axis, while,

b = length of the semi-major axis

Since we are told that the satellite distance to the surface of the moon varies from 953km to 466km, values of a and b is calculated by summing each length to the radius of the moon as follows:

a = radius of moon + the larger distance of the satellite = 1000+953 = 1,953km

b = radius of moon + the smaller distance of the satellite = 1000+466 = 1,466km

Thus, the equation of the ellipse would be:

x²/1953² + y²/ 1466² = 1

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3 years ago

Find the odds of each of the following events. (a) an event E with Pr(E) = 4/7 (b) an event E with Pr(E) = 0.6 (a) The odds are

Dafna1 [17]

Answer:

(a) The odds of event E is 4/3.

(b) The odds of event E is 3/2.

Step-by-step explanation:

Formula for probability of an event:

$Probability=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}$

Formula for odds of an event:

$odds=\frac{\text{Favorable outcomes}}{\text{Unfavorable outcomes}}$

(a)

It is given that

$P(E)=\frac{4}{7}$

The probability of unfavorable event

$P(E')=1-P(E)=1-\frac{4}{7}=\frac{3}{7}$

Odds of event E is

$odds=\frac{P(E)}{P(E')}$

$odds=\frac{\frac{4}{7}}{\frac{3}{7}}$

$odds=\frac{4}{3}$

Therefore the odds of event E is 4/3.

(b)

It is given that

$P(E)=0.6$

The probability of unfavorable event

$P(E')=1-P(E)=1-0.6=0.4$

Odds of event E is

$odds=\frac{P(E)}{P(E')}$

$odds=\frac{0.6}{0.4}$

$odds=\frac{3}{2}$

Therefore the odds of event E is 3/2.

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