Question

3a²−4a+9=0 Use the discriminant to determine the number of real solutions to the quadratic equation.

Answer 1

Answer:

None

Step-by-step explanation:

The discriminant of a quadratic equation is $b^2-4ac$. In this case, that is:

$(-4)^2-4(3)(9)=16-108=-92$

Since the discriminant is negative, the square root will be a complex number, and this equation must have no real solutions. Hope this helps!