Answer: 5 1/30
Step-by-step explanation:
8 + 4/5 - 2/3 - 3 - 1/10 = 5 + 1/30
This Question is Incomplete
Complete Question
As an aid to the establishment of personnel requirements, the director of a hospital wishes to estimate the mean number of people who are admitted to the emergency room during a 24-hour period. The director randomly selects 64 different 24-hour periods and determines the number of admissions for each. For this sample, X = 396 and S = 100. Using the sample standard deviation as an estimate for the population standard deviation, what size sample should the director choose if she wishes to estimate the mean number of admissions per 24-hour period to within 1 admission with 99% reliability, what size sample should she choose?
Answer:
Sample size n = 16
Step-by-step explanation:
We use the formula for Margin of Error for the question
Margin of Error = z × Standard deviation/√n
Margin of Error = 1
z score for 99% confidence interval = 2.576
Standard deviation = 100
1 = 2.576 × 100/√n
1 × √n = 257.6
√n = 257.6/1
n = √257.6
n = 16.049922118
Approximately = 16
Therefore, the sample size = 16
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Nothing is handed to you ....you need to work HARD to get what you want.
Answer:
The total number of boxes of canned food brought in by the three grades is 17.63 boxes
Step-by-step explanation:
To find the total number of canned foods brought in by the three grades, we will have to add the number of canned foods brought by each of the grades to each other. Careful attention has to be paid to the decimal points.
Canned foods brought by 6th graders: 5.75 boxes
Canned foods brought by 7th graders: 6.5 boxes
Canned foods brought by 6th graders: 7/1.3 boxes
We may have a slight challenge adding in 7/1.3 boxes to the other figures. What we can do now is to evaluate it to a decimal value by dividing it up.
7/ 1.3 will be the same thing as 7 divided by 1.3 = 5.38 boxes.
hence, we have 5.75 +6.5+ 5.38= 17.63 boxes
The total number of boxes of canned food brought in by the three grades is 17.63 boxes
