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3 years ago

What is -a-5/4(-8/3a+1)

Mathematics

1 answer:

insens350 [35]3 years ago

4 0

The simplified expression would be 7a/3 - 5/4.

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What is the answer to 284 times 45 to the power of 3

Alecsey [184]

Hey there!

284 * 45^3

= 284 * 45 * 45 * 45

= 284 * 2,025 * 45

= 284 * 91,125

= 25,879,500

Therefore, your answer is:

25,879,500

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

5 0

2 years ago

Which do you prefer: leaving √5 in radical form, or converting it to a decimal? Why? When would it be useful to use each?

Goshia [24]

Answer:

Leaving as a radical form

Why?

Because that's the whole value if you convert it to a decimal you cannot write all the numbers, and in the radical form it has all the numbers

It would be useful when we are working with equations for example the quadratic equation, if you get that x=√5, you would want the exact value. And there are more useful

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3 years ago

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HELP! I NEED THIS QUESTION ANSWERED ASAP!!!!!

inessss [21]

Answer:

3 ) Acute

Step-by-step explanation:

Acute Angle - An angle less than 90 degrees.

Right Angle - An angle that is exactly 90 degrees.

Obtuse Angle - An angle more than 90 degrees and less than 180 degrees.

Straight Angle - An angle that is exactly 180 degrees.

6 0

3 years ago

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In right triangle ABC, mC - 90° and AC BC. Which trigonometric ratio is cquivalent to sin b?

vaieri [72.5K]

Answer:

All trigonometric Ratios are $SinB = \frac{AC}{AB}$ , $SinA= \frac{CB}{AB}$ , $CosA= \frac{AC}{AB}$

And $Cos B = \frac{CB}{AB}$ .

Step-by-step explanation:

Given that,

A right angle triangle ΔABC, ∠C =90°.

Diagram of the given scenario shown below,

In triangle ΔABC :-

$Hypotenuse = AB\\Base = CB\\Perpendicular = AC$

So, $Sin\theta = \frac{perpendicular}{hypotenuse}$

$SinB = \frac{AC}{AB}$

Now, for ∠A the dimensions of trigonometric ratios will be changed.

Here the base for ∠A is AC , perpendicular side is CB and hypotenuse will be same for all ratios.

$SinA= \frac{CB}{AB}$

Again, $Cos\theta= \frac{base}{hypotenuse}$

Then, $CosA= \frac{AC}{AB}$

And $Cos B = \frac{CB}{AB}$ .

Hence,

All trigonometric Ratios are $SinB = \frac{AC}{AB}$ , $SinA= \frac{CB}{AB}$ , $CosA= \frac{AC}{AB}$

And $Cos B = \frac{CB}{AB}$ .

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4 years ago

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hichkok12 [17]

What’s the question?

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4 years ago

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