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Bumek [7]
3 years ago
11

Slope 1/2 = goes through (2, 6) ​

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
7 0
Y = 1/2x+5 I think that’s it
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How much trail mix will each person get if 5 people share 1/2 pound of trail mix?
Viktor [21]
1/2=0.5 0.5/5=0.1 Each person would get 10% of the half bag of trail mix.
6 0
3 years ago
What’s the inverse function of f(x)=4x^2-13
Cerrena [4.2K]

Answer:

. The inverse function is y=x−24 .

Step-by-step explanation:

6 0
3 years ago
Solve the equation<br> 80 = 2m<br> A) 4<br> B) 40<br> C) 160<br> D) 320
Masja [62]

Answer:

B)40

Step-by-step explanation:

80 = 2 times 40: 80 = 80

8 0
3 years ago
A regulation soccer field has an area of 59,400 square feet. If the length is 330 feet, what is the width in feet
Juli2301 [7.4K]

Answer:

The answer is 180 feet.

Step-by-step explanation:

Here's your equation. (330 x W = 59,400).  If you want to find the width then divide 59,400 by 330 and you get 180 feet.

You can check by multiplying 330 and 180 which will result in 59,000.

So the correct answer is 180 feet.

4 0
3 years ago
A person is standing on a cliff that is 200ft above a body of water. The person looks down at an angle of depression of 42o at a
velikii [3]

Answer:

524.5 feet

Step-by-step explanation:

Given: Height of cliff= 200 ft

           Angle of depression at sail boat is 42°

           Angle of depression at yacht is 15°

Lets assume distance sailboat from the bottom of cliff is "d_1"

And assume distance yacht from the bottom of cliff is "d_2"

Now using tangent rule to solve it.

we know, tan\theta = \frac{opposite}{adjacent}

Distance sailboat from the bottom of cliff; tan 42= \frac{200}{d_1}

Using trignometry table to know the value of tan 42°

⇒0.90= \frac{200}{d_1}

cross multiplying both side.

⇒ d_1= \frac{200}{0.90} = 222.22 \approx 222

∴ Distance sailboat from the bottom of cliff (d_1)= 222 feet

Distance yatch from the bottom of cliff; tan 15= \frac{200}{d_2}

Using trignometry table to know the value of tan 15°

⇒0.2679= \frac{200}{d_2}

cross multiplying both side.

⇒ d_2= \frac{200}{0.2679} = 746.54 \approx 746.5

∴Distance yacht from the bottom of cliff (d_2)= 746.5 feet.

Next, finding the distance between sailboat and yacht.

Distance between sailboat and yacht = d_2-d_1

⇒ Distance between sailboat and yacht= 746.5-222= 524.5\ ft

∴ Distance between sailboat and yacht is 524.5 feet.

3 0
3 years ago
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