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Elina [12.6K]
3 years ago
12

Maritza rolls two number cubes that are numbered 1 through 6. What is the probability that the total on both cubes will be a pri

me number?
Mathematics
2 answers:
fenix001 [56]3 years ago
4 0

Answer:

5/12 or 41.66666% or 42%

Step-by-step explanation:

There are two number cubes both listed as 1-6. In order to find the probability of the total on both cubes being a prime number, you'd have to first come up with the prime numbers possible by addition. You should get 2, 3, 5, 7, and 11.

After finding the numbers possible, you have to find each of the different number combinations that you could use to get there. You should get 15 different possibilities.

2:

1, 1

3:

1, 2

2, 1

5:

1, 4

4, 1

2, 3

3, 2

7:

1, 6

6, 1

2, 5

5, 2

3, 4

4, 3

11:

5, 6

6, 5

Now, you have to find the total possibilities. You should get 36.

1, 1

1, 2

1, 3

1, 4

1, 5

1, 6

2, 1

2, 2

2, 3

2, 4

2, 5

2, 6

3, 1

3, 2

3, 3

3, 4

3, 5

3, 6

4, 1

4, 2

4, 3

4, 4

4, 5

4, 6

5, 1

5, 2

5, 3

5, 4

5, 5

5, 6

6, 1

6, 2

6, 3

6, 4

6, 5

6, 6

Now all you have to do is divide the two numbers (15 and 36), and you should get 5/12 as an exact answer, or 41.66666 (repeating) %, which you can round up to 42%.

Dahasolnce [82]3 years ago
3 0

Answer: 50% Chance

Answer: 1/2

Step-by-step explanation: 2,3, and 5 are the prime numbers 1-6. That means 3/6 of those numbers are prime. 3/6 simplifies to 1/2 or 50%

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If g (x)= 3/2x+4, what is the value of g(2)?
Semmy [17]

Answer:

g(2) =7

Step-by-step explanation:

g (x)= 3/2x+4

Let x = 2

g (2)= 3/2 *2+4

      = 3 +4

      = 7

6 0
3 years ago
Read 2 more answers
Last one for today !
RSB [31]
Easy

4 and 1/3+7 and 1/5=4+1/3+7+1/5=4+7+1/3+1/5=11+5/15+3/15=11+8/15=11 and 8/15

answer is D
4 0
3 years ago
A publisher reports that 65% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is
muminat

Answer:

z=\frac{0.60 -0.65}{\sqrt{\frac{0.65(1-0.65)}{340}}}=-1.933  

The p value for this case can be calculated with this probability:

p_v =2*P(z  

For this case is we use a significance level of 5% we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion is different from 0.65 or 65%. We need to be careful since if we use a value higher than 65 for the significance the result would change

Step-by-step explanation:

Information given

n=340 represent the random sample taken

\hat p=0.60 estimated proportion of readers owned a laptop

p_o=0.65 is the value that we want to test

z would represent the statistic

p_v{/tex} represent the p valueHypothesis to testWe want to check if the true proportion of readers owned a laptop if different from 0.65
Null hypothesis:[tex]p=0.65  

Alternative hypothesis:p \neq 0.65  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.60 -0.65}{\sqrt{\frac{0.65(1-0.65)}{340}}}=-1.933  

The p value for this case can be calculated with this probability:

p_v =2*P(z  

For this case is we use a significance level of 5% we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion is different from 0.65 or 65%. We need to be careful since if we use a value higher than 65 for the significance the result would change

5 0
4 years ago
I don’t understand any of this and its dude tomorrow someone help ;)
faltersainse [42]
You should get the app "photomath" that'll help you out alot!!!
6 0
3 years ago
Given that x = 3 + 8i and y = 7 - i, match the equivalent expressions.
drek231 [11]

By applying operations for <em>complex</em> numbers, we have these:

  1. - 5 · x + y = - 8 - i 41
  2. - x · y = - 29 - i 53
  3. x · 2 · y = 58 + i 106
  4. 2 · x - 3 · y = - 15 + i 19

<h3>How to find four equivalent complex expressions</h3>

Herein we must apply the operations of summing two <em>complex</em> numbers, multiplying two <em>complex</em> numbers and multiplying a <em>complex</em> number by a <em>real</em> number, which are defined below:

Addition between two complex numbers

(a + i b) + (c + i d) = (a + c) + i (b + d)     (1)

Multiplication between two complex numbers

(a + i · b) · (c + i d) = (a · c - b · d) + i (b · c + a · d)

Multiplication of a complex number by a real number

k · (a + i b) = k · a + i k · b      (2)

Now we proceed to find the equivalent expressions:

- 5 · x + y = - 5 · (3 + i 8) + (7 - i) = (- 15 - i 40) + (7 - i) = - 8 - i 41

- x · y = - (3 + i 8) · (7 - i) = (- 3 - i 8) · (7 - i) = (- 21 - 8) + i (- 56 + 3) = - 29 - i 53

x · 2 · y = (3 + i 8) · 2 · (7 - i) = (3 + i 8) · (14 - i 2) = (42 + 16) + i (112 - 6) = 58 + i 106

2 · x - 3 · y = 2 · (3 + i 8) - 3 · (7 - i) = (6 + i 16) + (- 21 + i 3) = - 15 + i 19

To learn more on complex numbers: brainly.com/question/10251853

#SPJ1

6 0
2 years ago
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