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gavmur [86]
3 years ago
13

Find the distance between the points (1, 5) and (1, -4).

Mathematics
2 answers:
Ganezh [65]3 years ago
6 0

Answer:

9

Step-by-step explanation:

\tt distance=\sqrt{(1-1)^2+(-4-5)^2}=\sqrt{0^2+9^{2}}=\sqrt{9^2} =9

Snowcat [4.5K]3 years ago
5 0

The formula for distance between two points is:

\sqrt{(x_{2} -x_{1})^{2} + (y_{2} -y_{1})^{2}}

In this case:

x_{2} =1\\x_{1} =1\\y_{2} =-4\\y_{1} =5

^^^Plug these numbers into the formula for distance like so...

\sqrt{(1-1)^{2} + (-4-5)^{2}}

To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

First we have parentheses. Remember that when solving you must go from left to right

\sqrt{(1-1)^{2} + (-4-5)^{2}}

1 - 1 = 0

\sqrt{(0)^{2} + (-4-5)^{2}}

-4 - 5 = -9

\sqrt{(0)^{2} + (-9)^{2}}

Next solve the exponent. Again, you must do this from left to right

\sqrt{(0)^{2} + (-9)^{2}}

0² = 0

\sqrt{0 + (-9)^{2}}

(-9)² = 81

\sqrt{(0 + 81)}

Now for the addition

\sqrt{(0 + 81)}

81 + 0 = 81

√81

^^^This can be further simplified to...

9

***Remember that the above answers are in terms of units

Hope this helped!

~Just a girl in love with Shawn Mendes

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