Question

Find the distance between the points (1, 5) and (1, -4).

Answer 1

Answer:

9

Step-by-step explanation:

$\tt distance=\sqrt{(1-1)^2+(-4-5)^2}=\sqrt{0^2+9^{2}}=\sqrt{9^2} =9$

Answer 2

The formula for distance between two points is:

$\sqrt{(x_{2} -x_{1})^{2} + (y_{2} -y_{1})^{2}}$

In this case:

$x_{2} =1\\x_{1} =1\\y_{2} =-4\\y_{1} =5$

^^^Plug these numbers into the formula for distance like so...

$\sqrt{(1-1)^{2} + (-4-5)^{2}}$

To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

First we have parentheses. Remember that when solving you must go from left to right

$\sqrt{(1-1)^{2} + (-4-5)^{2}}$

1 - 1 = 0

$\sqrt{(0)^{2} + (-4-5)^{2}}$

-4 - 5 = -9

$\sqrt{(0)^{2} + (-9)^{2}}$

Next solve the exponent. Again, you must do this from left to right

$\sqrt{(0)^{2} + (-9)^{2}}$

0² = 0

$\sqrt{0 + (-9)^{2}}$

(-9)² = 81

$\sqrt{(0 + 81)}$

Now for the addition

$\sqrt{(0 + 81)}$

81 + 0 = 81

√81

^^^This can be further simplified to...

9

***Remember that the above answers are in terms of units

Hope this helped!

~Just a girl in love with Shawn Mendes