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Darya [45]
3 years ago
13

A circle is defined by the equation given below.

Mathematics
1 answer:
Ierofanga [76]3 years ago
5 0
The circle equation is in the format (x – h)2 + (y – k)2= r2, with the center being at the point (h, k) and the radius being "r".

x²+y²-8x-6y+2 =0 -----(a)
(x-4)² = x² - 8x + 16
(y-3)² = y² - 6y + 9

Equation (a) can be rewritten as:
(x-4)² + (y-3)² + 2 - 16 - 9 = 0
(x-4)² + (y-3)² = 23

The coordinates for the center of the circle is: ( 4,3)
The radius is √23=4.8
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3 years ago
A new car that costs $17,500 loses 25 percent of its value in the first year. How much is the loss of the value.
EastWind [94]

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4 0
3 years ago
Pls help me solve this question, also include step by step calculation ya. Thks
sp2606 [1]

\displaystyle\\Answer:\ x=\sqrt{2}\ \ \ \ \ x=-\sqrt{2}\ \ \ \ \ x=\frac{ln5}{2}

Step-by-step explanation:

5x^2-x^2e^{2x}+2e^{2x}=10

Let:\ x^2=t  \ \ \ \ \ e^{2x}=v\\Hence,\\5t-tv+2v^2=10\\5t-tv+2v^2-10=10-10\\5t-tv-10+2v^2=0\\t(5-v)-2(5-v)=0\\(5-v)(t-2)=0\\5-v=0\\5-v+v=0+v\\5=v\\5=e^{2x}

<em>Prologarithmize both parts of the equation:</em>

ln5=lne^{2x}\\ln5=2x*lne\\ln5=2x*1\\ln5=2x\\

<u><em> Divide both parts of the equation by 2:</em></u>

\displaystyle\\x=\frac{ln5}{2}

t-2=0\\t-2+2=0+2\\t=2\\x^2=2\\x=\sqrt{2} \\x=-\sqrt{2}

6 0
1 year ago
(1+v)(v-7) i need help to solve this question
kramer
(1 + v)(v - 7)

1*(v - 7) + v(v - 7)

1*v - 1*7 + v*v - v*7

v - 7 + v² - 7v

v² - 7v + v - 7

 v² - 6v - 7

I hope this helps.
4 0
3 years ago
30/10 as a whole number
mrs_skeptik [129]
3.

30 divided by 10 equals 3
7 0
3 years ago
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