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Darya [45]
3 years ago
13

A circle is defined by the equation given below.

Mathematics
1 answer:
Ierofanga [76]3 years ago
5 0
The circle equation is in the format (x – h)2 + (y – k)2= r2, with the center being at the point (h, k) and the radius being "r".

x²+y²-8x-6y+2 =0 -----(a)
(x-4)² = x² - 8x + 16
(y-3)² = y² - 6y + 9

Equation (a) can be rewritten as:
(x-4)² + (y-3)² + 2 - 16 - 9 = 0
(x-4)² + (y-3)² = 23

The coordinates for the center of the circle is: ( 4,3)
The radius is √23=4.8
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What is the next term in the sequence
Nesterboy [21]

Answer:

-5/2

Step-by-step explanation:

The next term will be,

→ -2/4

→ (-2-3)/(4÷2)

→ -5/2

Hence, the solution is -5/2.

8 0
2 years ago
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MARY PUT IN A TOTAL OF 16-1/2 8 FEET LONG. A NEARBY POLE IS 72 HOURS BABYSITTING DURING 5 DAYS FEET HIGH. HOW LONG IS ITS OF THE
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Answer: 3 hours and 18 minutes.

Step-by-step explanation:

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4 years ago
Explain how to solve 3^x-4=6 using the change of base formula log base b of y equals log y over log b. include the solution for
Alexxandr [17]

Answer:

x = log 10/log 3

Step-by-step explanation:

3^x - 4 = 6

3^x = 10

We take log base 3 of both sides since log_3 3^x is simply x.

log_3 3^x = log_3 10

x = log_3 10

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7 0
3 years ago
A sanitation department is interested in estimating the mean amount of garbage per bin for all bins in the city. In a random sam
bekas [8.4K]

Answer:

<em>The   95.7% confidence interval for the expected amount of garbage per bin for all bins in the city</em>

(48.937 , 50.863)

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given data random sample of 46 bins, the sample mean amount was 49.9 pounds and the sample standard deviation was 3.641

<em>The sample size 'n' =46</em>

<em>mean of the sample x⁻ = 49.9</em>

<em>Standard deviation of the sample S = 3.641</em>

<u>Confidence intervals:</u><em>-</em>

<em>The   95.7% confidence interval for the expected amount of garbage per bin for all bins in the city</em>

<em></em>(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha } \frac{S}{\sqrt{n} })<em></em>

<em>Degrees of freedom = n-1  = 46-1 =45</em>

<em>The tabulated value   t₀.₉₆ =   1.794 ( from t-table)</em>

<em></em>(49.9 - 1.794 \frac{3.641}{\sqrt{46} } ,49.9+ 1.794 \frac{3.641}{\sqrt{46} })<em></em>

(49.9 -0.9630 , 49.9+0.9630)

(48.937 , 50.863)

<u>Conclusion:</u>-

<em>The   95.7% confidence interval for the expected amount of garbage per bin for all bins in the city</em>

(48.937 , 50.863)

4 0
3 years ago
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