Answer:
The equation in standard form:
2x-y-10=0
Answer: D. 94.25 in²
Step-by-step explanation:
To find the total area, we will break the shape up into two different parts.
[] The rounded part is 39.25 in². Let us assume the rounded part is exactly half of a circle.
Area of a circle:
A = πr²
Use 3.14 for pi:
A = (3.14)r²
Find the radius:
d / 2 = r, 10 / 2 = 5 in
Subsittue:
A = (3.14)(5)²
A = 78.5 in²
Divide by 2 since it is only half:
78.5 in² / 2 = 39.25 in²
[] The triangle is 55 in².
Area of a triangle:
A = b*h/2
A = 11 * 10 / 2
A = 110 / 2
A = 55 in²
[] Total area. We will add the two parts together.
55 in² + 39.25 in² = 94.25 in²
Consists of two terms (A+B)
You have to first mess around with the first shape, ABCD, and split that into a rectangle and a right triangle. once you do that, it's pretty painstaking, but simple.
if you look at it you can tell that EFGH is just half the size, but the same ratios and everything.
So, you would just take every perimeter measurement from ABCD, and divide it by two and then sum them together.
2.5 + 1.5 + 4.0 + 2.0 = 10
95141 1404 393
Answer:
- arc BC: 8.55 cm
- chord BC: 8.03 cm
Step-by-step explanation:
The length of an arc that subtends central angle α will be ...
s = rα . . . . where α is in radians
The central angle BOC is twice the measure of angle QBC, so is 70°, or 7π/18 radians. So, the length of arc BC is ...
s = (7 cm)(7π/18) ≈ 8.55 cm . . . arc BC
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For central angle α and radius r, the chord subtending the arc is ...
c = 2r·sin(α/2)
c = 2(7 cm)sin(35°) ≈ 8.03 cm . . . . chord AB
