Can i pls get some help
1 answer:
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<h3>The Graph you need above </h3><h3>Step-by-step explaination : </h3><h3>Combine 1/3and x.</h3>
y<x/3+1/2
<h3>Use the slope-intercept form to find the slope and y-intercept.</h3><h3 />Slope: 1/3
y-intercept: 1/2
<h3>Graph a dashed line, then shade the area below the boundary line since y is less</h3><h3>than x/3+1/2.</h3><h3>y<x/3+1/2</h3>