Answer:
The answer: cougar population is 9 times the bear population
Step-by-step explanation:
∵ x = 15 ⇒ 15 years after study time
∵ f(x) = 830(0.8)^15 = 29.203 ≅ 29
From the table the cougar population after 15 years = 226
∴ The cougar population = 266 ÷ 29 = 9.172 ≅ 9 times the bear population
Answer: See the diagram below.
This diagram shows a closed filled in circle at -14 on the number line. Also, the shaded region is to the left of the closed circle. This visually represents values that are smaller than -14, or equal to -14.
The filled in circle is used to indicate "include this endpoint". In contrast, an open hole indicates "do not include this endpoint" which is only used if the inequality was 
instead of 
. The "or equal to" portion is why we include the endpoint.
Well because the line segment runs from the center of the circle to a point on the circumference, AB would represent the radius.
Log b 18 = logb 2 * 3 * 3
When multiplying logs, they are added together so:
logb 2 * 3 * 3 = logb 2 + logb 3 + logb 3
Logb 2 is given as 0.4307 and logb 3 is 0.6826
Now we have 0.4307 + 0.6826 + 0.6826 = 1.7959
Logb 18 = 1.7959
Answer:
- C
- B
- A
- E
- D
Step-by-step explanation:
1. All numbers on either of lists B or C are all the numbers 1..6, as in choice C.
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2. Numbers in B that are also in A are just 2 and 4. 6 is not in A. choice B.
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3. Numbers in both A and C are just the numbers in C. choice A.
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4. There are no numbers in both B and C, so B∩C is the empty set. Anything intersected with the empty set is the empty set. choice E.
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5. As in (4), but here, we want the union of A with the empty set. That result will be set A, choice D.
