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Juliette [100K]
3 years ago
15

47x + 31y = 63 31x + 47y = 15

Mathematics
1 answer:
NikAS [45]3 years ago
7 0

Answer:

x = 2, y = -1

Step-by-step explanation:

47x + 31y = 63...eqn 1

31x + 47y = 15...eqn 2

multiply eqn 1 by 47 to get eqn 3 and multiply eqn 2 by 31 to get eqn 4...

=> 2209x + 1457y = 2961...eqn 3

=> 961x + 1457y = 465...eqn 4

subtract eqn 4 from eqn 3

=> 1248x = 2496

=> x =2

subst x =2 in eqn 1

=> 94 + 31y = 63

=> 31y = -31

=> y = -1

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X^2-x+2=0<br> Please use the quadratic formula
Ainat [17]

Answer:

\boxed{\sf x=\cfrac{1\pm \sqrt{-7} }{2}}

Step-by-step explanation:

\sf x^2-x+2=0

<u>Use quadratic formula:</u>

\boxed{\sf \frac{-b\pm \sqrt{b^2-4ac}}{2a}}

\sf a=1, b=-1, c=2

___________________________

\sf x_1,_2=\cfrac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\times \:1\times \:2}}{2\times \:1}

  • \sf \sqrt{\left(-1\right)^2-4\times \:1\times \:2}
  • \sf =\sqrt{-7}

_________________

\sf x_1,_2\cfrac{-\left(-1\right)\pm \sqrt{-7}}{2\times \:1}

  • \sf -(-1)=1
  • 2\times 1=2

\sf x_1,_2=\cfrac{1\pm \sqrt{-7} }{2}

_______________________________________

<u>Learn more: brainly.com/question/22286698</u>

4 0
2 years ago
I NEED HELP
bixtya [17]

The scale factor that was used to create triangle J’K’L’ is 1/3

<h3>How to determine the scale factor?</h3>

From the graph, we have the following highlights:

KL = 3

K'L' = 1

The scale factor (k) from JKL to J'K'L is calculated as:

Scale factor = K'L'/KL

This gives

k = 1/3

Hence, the scale factor that was used to create triangle J’K’L’ is 1/3

Read more about dilation at:

brainly.com/question/3457976

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5 0
2 years ago
PLEAASE HELP DUE TODAY
Kryger [21]

Answer:

I'm not sure but try 13.5.

Step-by-step explanation:

It might not be correct sorry

8 0
3 years ago
Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2, and the profit
Mademuasel [1]

<u>Answer:</u>

y = -\frac{2}{3}x + 490

gradient = = -\frac{2}{3}

y-intercept = 490

<u>Step-by-step explanation:</u>

• The slope-intercept form of an equation takes the general form:

\boxed{y = mx + c},

where:

m = slope,

c = y-intercept.

• We are given the equation:

2x + 3y = 1470

To change this into the slope-intercept form, we must make y the subject:

3y = -2x + 1470          [subtract 2x from both sides]

⇒ y = -\frac{2}{3}x + \frac{1479}{3}        [divide both sides by 3]

⇒ y = -\frac{2}{3}x + 490

• Comparing this equation with the general form equation, we see that:

m = -\frac{2}{3}

c = 490.

This means that the gradient is \bf -\frac{2}{3}, and the y-intercept is \bf 490.

6 0
2 years ago
I really need help with this and how find the Surface area and Lateral area and what is the length and width for both of the fig
Ksenya-84 [330]

Answer:

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Step-by-step explanation:

6 0
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