<u>Answer:</u>
Point Form:
(−5,1)
Equation Form:
x=−5, y=1
<u>Step-by-step explanation:</u>
Solve for the first variable in one of the equations, then substitute the result into the other equation.
1. x=5y−10
2. 20y−30=−10
3. y=1
4. x=−5
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Number of milk cartons put out for breakfast = 100
Number of cartons remaining at the end = 27
Number of cartons consumed = 100 - 27 = 73
Ratio of cartons remaining / cartons consumed = 27/73
Start the equation by putting the equations equal to each other 3x+14=7x-10
Next +10 on both sides
3x+14=7x-10
+10 +10
You are left with 3x+24=7x
because the 10's canceled each other out.
Next -3x on both sides
3x+24=7x
-3x +3x
You are left with 24= 10x
because like before the 3's canceled each other out
Now you will divide both sides by 10
24=10x
---- -----
10 10
2.4= X is the answer!
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>