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3 years ago

What is the value of X?

Mathematics

1 answer:

VashaNatasha [74]3 years ago

3 0

Answer:

considering the above 45*

to make the line that would represent 180*

180 - 45 = 135

(2 / 135 - 5)

62.5

62.5 is your answer

Step-by-step explanation:

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Use the distributive property to remove the parenthesis -4(-5w-3u+2)

lisov135 [29]

You multiply -4 to everything inside of the parenthesis which is 20w+12u-8

6 0

3 years ago

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Que is on pic.i can't able to type in text.

ad-work [718]

It's not difficult to compute the values of $A$ and $B$ directly:

$A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}$
$A=\tan^{-1}(\sin\theta)-\dfrac\pi4$

$B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt$
$B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}$
$B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2$

Let's assume $0$ , so that $|\csc\theta|=\csc\theta$ .

Now,

$\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}$
$\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}$
$\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)$
$\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)$

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in $A$ and $B$ .

3 0

3 years ago

Haley had 7 pens. All of the pens are either blue or black, And there are 3 more blue pens than black pens. How many black pens

MaRussiya [10]

Hello! Haley has 7 pens, with 3 more of them being blue than black. If you do some mental math, you know that 5 is 3 more than 2 and 2 + 5 is 7. So Haley has 5 blue pens and 2 black pens.

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4 years ago

An online furniture store sells chairs for $150 each and tables for $550 each. Every day, the store can ship a maximum of 40 pie

Katen [24]

Answer:

minimum of 13 chairs must be sold to reach a target of $6500

and a max of 20 chairs can be solved.

Step-by-step explanation:

Given that:

Price of chair = $150

Price of table = $400

Let the number of chairs be denoted by c and tables by t,

According to given condition:

t + c = 30 ----------- eq1

t(150) + c(400) = 6500 ------ eq2

Given that:

10 tables were sold so:

t = 10

Putting in eq1

c = 20 (max)

As the minimum target is $6500 so from eq2

10(150) + 400c = 6500

400c = 6500 - 1500

400c = 5000

c = 5000/400

c = 12.5

by rounding off

c = 13

So a minimum of 13 chairs must be sold to reach a target of $6500

i hope it will help you! mark me as brainliest pls

§ALEX§

6 0

4 years ago

Will mark you brainless 100 pts plz help

PolarNik [594]

Answer:

1,2,3,4,5

5,10,15,20,25

Step-by-step explanation:

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3 years ago

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